c - 清除数组中重复项的函数

Question

我正在尝试创建一个函数来清除数组中重复的数字，但似乎我无法弄清楚我缺少什么来删除重复项。只是为了更清楚:该函数不应变为无效。

[1,2,3,3,4] -> [1,2,3,4]
[4,2,5,1]->[4,2,5,1]
[32,21,2,5,2,1,21,4]->[32,21,2,5,1,4]

我的数组中不应该是空格，函数应该返回cleaned 数组中的唯一元素，其中 cleaned 定义为“整数的非重复”

#include <stdio.h>

int generateUniqeList(int *list, int length);

int main()
{
    int list[6] = { 5, 5, 4, 3, 2, 1 };
    int duplicate = generateUniqeList(list, 6);

    for (int i = 0; i < 6; i++)
    {
        printf("%d\n", list[i] - 1); //Here i am able to change the value of the duplicates with the - 1
    }
    getchar();

    return 0;
}


int generateUniqeList(int *list, int length)
{
    int duplicate = 0;

        for (int i = 0; i < length; i++)
        {
            if (list[i] == list[i])
                duplicate = list[i];
        }
    return duplicate;
}

Answer 1

#include <stdio.h>
#include<string.h>


void generateUniqeList(int *list, int length);

int main()
{
  int list[6] = { 5, 5, 4, 3, 2, 1 };
  generateUniqeList(list, 6);

  for (int i = 0; i < 6; i++)
  {
    printf("%d", list[i]); 
  //Here i am able to change the value of the duplicates with the - 1
  }
  putchar('\n');

  return 0;
}


void generateUniqeList(int *list, int length){
  int i ,j,k;
  for (i = 0; i < length; i++) {
      for (j = i + 1; j < length;) {
         if (list[j] == list[i]) {
            for (k = j; k < length; k++) {
               list[k] = list[k + 1];
            }
            length--;
         } else
            j++;
      }
   }

}