node.js - 如何在 Node.js 中提取完整的 URL，而不使用 HTTP？

Question

我想提取除 HTTP 之外的完整 URL。我用过Domain和 url .

这是我的代码

var url = require('url');
var domain=require('domain.js');

var url_parts = 'http://static01.nyt.com/images/2014/11/17/business/billboardjump/billboardjump-master675.jpg'; 

var website=domain(url.parse(url_parts));
var querystring = (url.parse(url_parts, true)).path;

console.log(website+querystring);

但只有我得到

'nyt.com/images/2014/11/17/business/billboardjump/billboardjump-master675.jpg' 

而不是

'static01.nyt.com/images/2014/11/17/business/billboardjump/billboardjump-master675.jpg' 

提前致谢。

Answer 1

只需计算协议(protocol)长度并将其删除:

var u = 'http://static01.nyt.com/images/2014/11/17/business/billboardjump/billboardjump-master675.jpg';
var protocol = url.parse(u).protocol;
console.log(u.slice((protocol + '//').length));