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python - 如何使用 cpython 将结构数组传递给 DLL 函数?

转载 作者:太空宇宙 更新时间:2023-11-03 23:37:04 25 4
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#include <stdio.h>

struct struct_data {
int price;
char list[255];
int count;
};

__declspec(dllexport) void __stdcall testcall(struct struct_data *array_data) {

int i = 0;
while(array_data[i].price != 0) { // array_data is guaranteed to have a zero somewhere inside memory allocated for the array
printf("%d\n", array_data[i].price);
i++;
}

}

我尝试使用 cpython 从 Python 调用它,如下所示:

# C Backend imports
import os
import sys
import ctypes

# load DLL
dll = ctypes.WinDLL('C:\\Users\\user\Documents\\Pelles C Projects\\MarketlibDLL\\MarketlibDLL.dll')

class struct_data(ctypes.Structure):
_fields_ = [
('price', ctypes.c_int),
('list', ctypes.c_char * 255),
('count', ctypes.c_int),
]

d = struct_data() * 100 # I try to do: struct struct_data d[100];
d[0].price = 100
d[0].list = "ABC"
d[0].count = 3
d[1].price = 0

dll.testcall.argtypes = [ctypes.POINTER(struct_data)]
dll.testcall(d)

---------------------------------------------------------------------------
TypeError Traceback (most recent call last)
<ipython-input-2-36161e840b5f> in <module>
----> 1 d = struct_data() * 100
2 d[0].price = 100
3 d[0].list = "ABC"
4 d[0].count = 3
5 d[1].price = 0

TypeError: unsupported operand type(s) for *: 'struct_data' and 'int'

最佳答案

[Python 3.Docs]: ctypes - A foreign function library for Python具有所有必需的信息(Arrays 部分包含一个完美映射当前场景的示例)。

将您的代码修改为(为了便于阅读,分成两行):

struct_data_array_100 = struct_data * 100  # !!! This is a type (array consisting of 100 struct_data elements) !!!
d = struct_data_array_100() # Instantiate the array type
#d[0].price ...
# ...

关于python - 如何使用 cpython 将结构数组传递给 DLL 函数?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/57645636/

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