node.js - 在nodejs中使用promise执行一系列命令

Question

我想使用 Q Promise 通过 Nodejs 中的串行线逐步处理一系列命令。

var cmdArr = ['cmd1', 'cmd2','cmd3'];

我不知道如何构建这个。我想过这样的事情，但没有成功:

Q().then(function() {
  cmdArr.forEach(command) {
     //here to initialize the promise??
  }
});

重要的是保持顺序并能够在每个步骤之间使用 Q.delay。

Answer 1

假设您要执行的命令是某种异步函数调用:

var Q = require('q');

// This is the function you want to perform. For example purposes, all this
// does is use `setTimeout` to fake an async operation that takes some time.
function asyncOperation(input, cb) {
  setTimeout(function() {
    cb();
  }, 250);
};

function performCommand(command) {
  console.log('performing command', command);
  // Here the async function is called with an argument (`command`),
  // and once it's done, an extra delay is added (this could be optional
  // depending on the command that is executed).
  return Q.nfcall(asyncOperation, command).delay(1000);
}

// Set up a sequential promise chain, where a command is executed
// only when the previous has finished.
var chain = Q();
[ 'cmd1', 'cmd2', 'cmd3' ].forEach(function(step) {
  chain = chain.then(performCommand.bind(null, step));
});

// At this point, all commands have been executed.
chain.then(function() {
  console.log('all done!');
});

我对 q 不太熟悉，所以它可能会做得更好。

为了完整起见，这里是使用 bluebird 的版本:

var Promise = require('bluebird');

...

var asyncOperationAsPromised = Promise.promisify(asyncOperation);

function performCommand(command) {
  console.log('performing command', command);
  return asyncOperationAsPromised(command).delay(1000);
}

Promise.each(
  [ 'cmd1', 'cmd2', 'cmd3' ],
  performCommand.bind(null)
).then(function() {
  console.log('all done!');
});