gpt4 book ai didi

c# - 如何使用 XML 序列化抽象创建单例

转载 作者:太空宇宙 更新时间:2023-11-03 23:34:14 25 4
gpt4 key购买 nike

我正在尝试使用持久保存到 XML 文件的单例模式创建通用存储库。目前有 3 个具体的存储库,每个都从不同的 XML 文件加载。我无法弄清楚如何从 XML 文件中正确抽象存储库的创建。这是我的这个存储库的一个实现类。

模型

public interface IEntity
{
string Name { get; }
}

public class Game : IEntity
{
[XmlElement("Name")]
public string Name { get; set; }

[XmlElement("ExecutablePath")]
public string ExecutablePath { get; set; }

private Game() { } // Required for XML serialization.

public Game(string name, string executablePath)
{
Name = name;
ExecutablePath = executablePath;
}
}

存储库

public interface IRepository<TEntity> where TEntity: IEntity
{
List<TEntity> Items { get; }

void Add(TEntity entity);
void Delete(TEntity entity);
}

public abstract class Repository<TEntity> : IRepository<TEntity> where TEntity : IEntity
{
public abstract List<TEntity> Items { get; set; }

private static Repository<TEntity> _instance;
public static Repository<TEntity> Instance
{
get
{
if (_instance == null)\
_instance = RepositoryFactory<Repository<TEntity>>.LoadFromFile();

return _instance;
}
}

public void Add(TEntity entity)
{
Items.Add(entity);
}

public void Delete(TEntity entity)
{
Items.Remove(entity);
}
}

public static class RepositoryFactory<TRepository>
{
public static TRepository LoadFromFile()
{
using (TextReader reader = new StreamReader("Games.xml"))
{
XmlSerializer serializer = new XmlSerializer(typeof(TRepository));
return (TRepository)serializer.Deserialize(reader);
}
}
}

[XmlRoot("Games")]
public class GameRepository : Repository<Game>
{
[XmlElement("Game")]
public override sealed List<Game> Items { get; set; }

private GameRepository()
{
Items = new List<Game>();
}
}

当尝试调用“GameRepository.Instance”时,我得到了这个非常普遍的异常: {"<Games xmlns=''> was not expected."}

不可否认,这是我第一次尝试将这些设计模式(单例/工厂)融合在一起,因此这种方法从一开始就可能是完全错误的。我无法从异常中准确诊断出什么问题(内部异常为空),所以我希望知道这些模式的人可以帮助我。

更新

示例 Games.xml 文件

<?xml version="1.0" encoding="utf-8" ?>
<Games>
<Game>Test</Game>
<ExecutablePath>ExecutablePath</ExecutablePath>
</Games>

示例代码 - 仍然失败

class Program
{
static void Main(string[] args)
{
IRepository<Game> gameRepository = new XmlRepository<Game>();
Test test = new Test(gameRepository);

Console.WriteLine(test.GetFirstGame());
Console.Read();
}
}
class Test
{
private IRepository<Game> GameRepository { get; set; }

public Test(IRepository<Game> gameRepository)
{
GameRepository = gameRepository;
}

public string GetFirstGame()
{
return GameRepository.Items.Value.FirstOrDefault().Name;
}
}

最佳答案

我认为 GameRepository 在这里是多余的。您可以将游戏列表直接序列化/反序列化为 xml 文件(见下文)。至于整体设计,看起来你有点疯狂(在静态上下文中做太多)。这使得代码难以测试和更改。我建议阅读依赖注入(inject),并使用 IoC 容器来管理对象(包括单例)的生命周期。我能够让您的示例对读/写代码进行一些修改,并且更改了设计以从具体实现中消除对单例的任何担忧。通过这种方式,客户端代码可以选择是否使用单例。希望这会有所帮助。

public class XmlRepository<TEntity> : IRepository<TEntity> where TEntity : IEntity
{
private readonly string _filePath;
private readonly Lazy<List<TEntity>> _items;

public XmlRepository(string filePath)
{
_filePath = filePath;
_items = new Lazy<List<TEntity>>(Load);
}

public IEnumerable<TEntity> Items
{
get { return _items.Value; }
}

public void Add(TEntity item)
{
if (_items.Value.Contains(item))
throw new InvalidOperationException();

_items.Value.Add(item);
}

public void Delete(TEntity item)
{
_items.Value.Remove(item);
}

public void Save()
{
var serializer = new XmlSerializer(typeof(List<TEntity>));
using (var reader = File.CreateText(_filePath))
{
serializer.Serialize(reader, _items.Value);
}
}

private List<TEntity> Load()
{
if (!File.Exists(_filePath))
return new List<TEntity>();

var serializer = new XmlSerializer(typeof(List<TEntity>));
using (var reader = File.OpenText(_filePath))
{
return (List<TEntity>)serializer.Deserialize(reader);
}
}
}

public static class RepositorySingletons
{
private static IRepository<Game> _gameRepository;

public static IRepository<Game> GameRepository
{
get
{
return _gameRepository ??
(_gameRepository = new XmlRepository<Game>("Game.xml"));
}
}
}

public class MyGamesApplication
{
private readonly IRepository<Game> _gameRepository;

public MyGamesApplication(IRepository<Game> gameRepository)
{
// I don't care if I have a singleton or not :)
_gameRepository = gameRepository;
}

public MyGamesApplication()
{
// I need to fetch a singleton :(
_gameRepository = RepositorySingletons.GameRepository;
}

public void Run()
{
var game = new Game
{
Id = 55378008,
Title = "Abe's Oddysee"
};
_gameRepository.Add(game);
Console.WriteLine("Added game " + game.Title);

_gameRepository.Save();
Console.WriteLine("Saved games");
}
}

关于c# - 如何使用 XML 序列化抽象创建单例,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/31102905/

25 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com