c - 将指针数组传递给函数

Question

我正在尝试将文件指针数组传递给函数(不确定术语)。谁能解释发送“in[2]”的正确方法？谢谢。

    #include<stdio.h>
    #include<stdlib.h>

    void openfiles (FILE **in[], FILE **out)
    {
        *in[0] = fopen("in0", "r");
        *in[1] = fopen("in1", "r");
        *out   = fopen("out", "w");
    }

    void main()
    {
        FILE *in[2], *out;

        openfiles (&in, &out);
        fprintf(out, "Testing...");

        exit(0);
    }

Answer 1

尝试:

void openfiles (FILE *in[], FILE **out)
{
    in[0] = fopen("in0", "r");
    in[1] = fopen("in1", "r");
    *out   = fopen("out", "w");
}

并将其称为打开文件(输入、输出)；。此外，“指针数组”是不明确的。也许称它为“FILE 指针数组”？