我声明了一个包含 json 数据的数组,然后当我init
时应该读取该数组并将其显示在 div 上。但是现在什么也没显示,谁能帮我检查我的代码,我犯了什么错误。谢谢。
JS Fiddle
HTML
<script>
$(function() {
var array = [];
array[0] = {
"no": "1",
"name": "fruit",
"value": "mango",
"totalvote": "75"
};
array[1] = {
"no": "2",
"name": "fruit",
"value": "apple",
"totalvote": "10"
};
array[2] = {
"no": "3",
"name": "fruit",
"value": "orange",
"totalvote": "5"
};
array[3] = {
"no": "4",
"name": "fruit",
"value": "banana",
"totalvote": "45"
};
PG.init("popup_survey_whitebox_selection", "1", array);
PG.callpopup();
PG.render_1();
});
</script>
JS
var PG = {
divid: "",
multiselection: "",
optionitem: [],
/* type:"", */
init: function (divid, multiselection, optionitem) {
/* PG.type = type;*/
PG.divid = divid;
PG.multiselect = multiselection;
PG.optionitem = optionitem;
},
test: function () {
for (var i = 0; PG.optionitem.length > i; i++) {
alert(PG.optionitem[i].name);
}
},
callpopup: function () {
$("#popup_survey_whitebox_content").hide();
var orig = '', // create var to cache the original text
newText = ''; // create var to cache the new Text with "..."
$("label#popup_survey_label_title").text(function (index, currentText) {
orig = currentText;
newText = currentText.substr(0, 30);
if (currentText.length > 30) newText += "...";
return newText;
});
$("#popup_survey_whitebox").hover(function () {
$('#popup_survey_whitebox_content').stop().animate({
opacity: 1,
height: "toggle"
}, 500, function () {
$("label#popup_survey_label_title").text(orig); // Here put the original text.
}).css('position', 'relative');
}, function () {
$('#popup_survey_whitebox_content').stop().animate({
opacity: 1,
height: "toggle"
}, 500, function () {
$("label#popup_survey_label_title").text(newText); // Here put the new text with "..."
}).css('position', 'relative');
});
$("#popup_survey_end_whitebox").click(function () {
$("#popup_survey_whitebox").remove();
});
},
render_1: function () {
$.each(array, function (i, obj) {
if (PG.multiselect == 1) {
var selection = "<li class='popup_survey_whitebox_li'></li><input class='the_checkbox' type='radio' id=" + obj.value + " name=" + obj.name + " value=" + obj.value + ">" +
"<label class='popup_survey_whitebox_label' for=" + obj.value + ">" + obj.no + ". " + obj.value + "</label>" +
"<div class='popup_survey_whitebox_progressbar'><div class='popup_survey_whitebox_progressbar_inner' for=" + obj.value + " style='width:" + obj.totalvote + "%;'>" +
"</div></div>" +
"<div id='popup_survey_whitebox_percent' class='popup_survey_whitebox_percent'>" + obj.totalvote + "%</div>";
} else {
var selection = "<li class='popup_survey_whitebox_li'></li><input class='the_checkbox' type='checkbox' id=" + obj.value + " name=" + obj.name + " value=" + obj.value + ">" +
"<label class='popup_survey_whitebox_label' for=" + obj.value + ">" + obj.no + ". " + obj.value + "</label>" +
"<div class='popup_survey_whitebox_progressbar'><div class='popup_survey_whitebox_progressbar_inner' for=" + obj.value + " style='width:" + obj.totalvote + "%;'>" +
"</div></div>" +
"<div id='popup_survey_whitebox_percent' class='popup_survey_whitebox_percent'>" + obj.totalvote + "%</div>";
}
$("#" + PG.divid).append(selection);
});
var survey_button = "<br><input id='submit_btn' type='button' class='whiteboxbutton whiteboxbutton-small' value='Finish' style='width:100%;'>";
$("#popup_survey_label_title").append("What is your favorite fruit??What is your favorite fruit??");
/*$("#popup_survey_whitebox_title").append();*/
$("#popup_survey_whitebox_inner_title").append("Please select 1 fruit only:");
$('#popup_survey_whitebox_button').append(survey_button);
$('.the_checkbox').on('change', function (evt) {
$('.popup_survey_whitebox_percent').css('display', 'block');
$('.popup_survey_whitebox_progressbar').css('display', 'block');
$(".popup_survey_whitebox_button").show();
if ($(this).siblings(':checked').length >= PG.multiselect) {
this.checked = false;
}
});
},
save: function () {}
}
我安慰并收到此错误 Uncaught ReferenceError: array is not defined 但我必须在 html 上声明。
除了 closure
之外,还有其他方法可以解决此错误。因为,你已经在 PG
中有了 optionitem
并且你已经将 optionitem
传递给它,你也可以在 render_1 中使用它
方法。
改变
$.each(array, function (i, obj) {
到
$.each(PG.optionitem, function (i, obj) {
有了它,您就不需要将 array
定义为可能与其他变量冲突的全局变量。
http://jsfiddle.net/5qnhcudp/2/
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