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python - 将两个参数(int 和数组)传递给嵌入式 Python 函数

转载 作者:太空宇宙 更新时间:2023-11-03 23:19:15 26 4
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我需要从我的模块调用 Python 函数并为其设置两个参数:int 和 array。

现在我在调用这个函数的过程中遇到了段错误,我不知道我做错了什么。有人可以指定我的错误在哪里吗?

我的 Python 模块 app.py 中的函数。如果我从 Python 代码中调用它,它会起作用:

def get_model(rate, signal):
mfcc_train = MFCC().compute(rate, signal)
with open('mfcc_test', 'wb') as f:
pickle.dump(mfcc_train, f)
return clf()._fit(mfcc_train)

调用上述函数的 C 代码。最后一个 Spring 是“打电话之前”

#include <Python.h>
#include <stdio.h>
#include "wav.h"
#include <numpy/arrayobject.h>

int main(int argc, char *argv[])
{
PyObject *pName, *pModule, *pDict, *pFunc, *pValue, *pArgs;
uint8_t *samples = NULL;

wavread("test.wav", &samples);

printf("No. of channels: %d\n", header->num_channels);
printf("Sample rate: %d\n", header->sample_rate);
printf("Bit rate: %dkbps\n", header->byte_rate*8 / 1000);
printf("Bits per sample: %d\n\n", header->bps);
printf("Sample 0: %d\n", samples[0]);
printf("Sample 1: %d\n", samples[1]);
// Initialize the Python Interpreter
printf("Before init\n");
Py_Initialize();
PyObject *sysPath = PySys_GetObject("path");
const char *scriptDirectoryName = ".";
PyObject *path = PyUnicode_FromString(scriptDirectoryName);
int result = PyList_Insert(sysPath, 0, path);
printf("after init\n");
// Build the name object
pName = PyUnicode_DecodeFSDefault(argv[1]);
printf("after pname %s %d\n", argv[1], pName == NULL ? 1 : 0);

// Load the module object
pModule = PyImport_Import(pName);
printf("after pmodule %d\n", pModule == NULL ? 1 : 0);

// pFunc is also a borrowed reference
pFunc = PyObject_GetAttrString(pModule, "get_model");
printf("after pfunc\n");

if (PyCallable_Check(pFunc))
{
pArgs = PyTuple_New(2);
printf("after pytuple\n");
PyTuple_SetItem(pArgs, 0, PyLong_FromLong(header->sample_rate));
printf("after set item\n");
uint8_t* array = malloc(header->datachunk_size);
int dims[1];
dims[0] = header->datachunk_size;
printf("alloc\n");
import_array();
PyObject* pSamples = PyArray_SimpleNewFromData(1, dims, NPY_INT8, (void*)samples);
printf("pSamples\n");
PyArray_ENABLEFLAGS((PyArrayObject*)pSamples, NPY_ARRAY_OWNDATA);
PyTuple_SetItem(pArgs, 1, pSamples);
printf("Before calling\n");
pValue = PyObject_CallObject(pFunc, pArgs);
printf("After calling\n");
} else
{
PyErr_Print();
}

printf("pValue: %d\n", pValue);
// Clean up
Py_DECREF(pModule);
Py_DECREF(pFunc);
Py_DECREF(pName);

// Finish the Python Interpreter
Py_Finalize();

free(header);
free(samples);
}

UPD:更新了代码,修复了一个问题。但另一个问题仍然存在。它在 PyObject* pSamples = PyArray_SimpleNewFromData(1, dims, NPY_INT8, (void*)samples); 行中。而且我找不到它有什么问题。

还有 wav.h 以防万一:

#include <inttypes.h>
#include <stdlib.h>
#include <sys/types.h>
#include <sys/stat.h>
#include <fcntl.h>
#include <err.h>
typedef struct {
char chunk_id[4];
uint32_t chunk_size;
char format[4];
char fmtchunk_id[4];
uint32_t fmtchunk_size;
uint16_t audio_format;
uint16_t num_channels;
uint32_t sample_rate;
uint32_t byte_rate;
uint16_t block_align;
uint16_t bps;
char datachunk_id[4];
uint32_t datachunk_size;
}WavHeader;
WavHeader *header;
void wavread(char *file_name, int16_t **samples)
{
int fd;
if (!file_name)
errx(1, "Filename not specified");
if ((fd = open(file_name, O_RDONLY)) < 1)
errx(1, "Error opening file");
if (!header)
header = (WavHeader*)malloc(sizeof(WavHeader));
if (read(fd, header, sizeof(WavHeader)) < sizeof(WavHeader))
errx(1, "File broken: header");
if (strncmp(header->chunk_id, "RIFF", 4) ||
strncmp(header->format, "WAVE", 4))
errx(1, "Not a wav file");
if (header->audio_format != 1)
errx(1, "Only PCM encoding supported");
if (*samples) free(*samples);
*samples = (int16_t*)malloc(header->datachunk_size);
if (!*samples)
errx(1, "Error allocating memory");
if (read(fd, *samples, header->datachunk_size) < header->datachunk_size)
errx(1, "File broken: samples");
close(fd);
}

最佳答案

如果没有 header 的定义很难判断,但我相信问题出在行上

PyTuple_SetItem(pArgs, 0, header->sample_rate);

PyTuple_SetItem 需要一个 Python 对象,而您将我认为是整数的东西传递给它,它被误解为 PyObject*

我怀疑你想要

PyTuple_SetItem(pArgs, 0, PyInt_FromLong(header->sample_rate));

(Python3 中的PyLong_FromLong)


第二个问题:您 free samples 两次。首先你将它传递给 numpy 并告诉 numpy 它拥有数据:

PyObject* pSamples = PyArray_SimpleNewFromData(1, dims, NPY_INT8, (void*)samples);
PyArray_ENABLEFLAGS((PyArrayObject*)pSamples, NPY_ARRAY_OWNDATA);

然后在代码的末尾释放它

free(samples);

我怀疑您打算将新分配的 array 传递给 numpy 而不是 samples。 (如果是这种情况,您仍然需要在它们之间复制数据)

UPD:评论中的一个更正确的解决方案是将 dims 类型从 int 更改为 npy_intp

关于python - 将两个参数(int 和数组)传递给嵌入式 Python 函数,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/45737189/

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