c# - Hangman - GDI+ 问题

Question

我有点难受。我开始开发基于 GUI 的 Hangman 游戏，用于娱乐。但是，我遇到了一些问题。

需要猜的单词已经转换为char数组。但是，当用户输入字符以猜测单词时，CheckLetter() 方法似乎不起作用，尽管它可以正确调用。由于字母没有出现在屏幕上，所以当它们被正确猜测时。

如果你能指引正确的方向，我将不胜感激......

using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Windows.Forms;

namespace HangmanV1._0
{
    public partial class Main : Form
    {
        private Graphics g;

        //Stores words characters
        private char[] WordCharactes;

        //Cloned array size of word characters, though data only appears in the elements
        //when characters are matched succesfully
        private char[] GuessedLetters;

        public Main()
        {
            InitializeComponent();
        }

        public void GetWord(string Word, int NumberOfCharacters)
        {
            //Declares new char array
             WordCharactes = new char[NumberOfCharacters];
             GuessedLetters = new char[NumberOfCharacters];

            //Converts word to char array
             WordCharactes = Word.ToCharArray();
        }

        private void btnPlay_Click(object sender, EventArgs e)
        {
            //invokes the method by passing the word required to be guessed, specified by the user
            GetWord(tbWordToGuess.Text, tbWordToGuess.Text.Length);
            grbNewGame.Visible = false;

            //Draw hangman game board
            DrawWord(g);
        }

        public void DrawWord(Graphics e)
        {
            //Line Coordinates 
            int LinePointX = 50;
            int LinePointY = 80;
            int LetterPoint = 50;

            for (int i = 0; i < WordCharactes.Length; i++)
            {
                //Draws dashed unser letters, highlights how many letters to guess
                e.DrawLine(new Pen(Color.Black, 5), new PointF(LinePointX, 300), new PointF(LinePointY, 300));


                //Draws letters that have been correctly guessed
                e.DrawString(GuessedLetters[i].ToString(), new Font("Arial", 18), Brushes.Black, new PointF(LetterPoint, 270));

                //Steadily increments line 
                LetterPoint += 40;
                LinePointX += 40;
                LinePointY += 40;
            }
        }

        public void CheckLetter(char Letter)
        {
            this.Refresh(); //<-- Edit: adding this solved my problem

            //Compares letters
            for (int i = 0; i < WordCharactes.Length; i++)
            {
                if (WordCharactes[i] == Letter)
                {
                    GuessedLetters[i] = WordCharactes[i];
                }
            }
        }

        private void Form1_Load(object sender, EventArgs e)
        {
            g = this.CreateGraphics();
        }

        private void exitToolStripMenuItem_Click(object sender, EventArgs e)
        {
            //Exits enviroment
            Environment.Exit(0);
        }

        private void btnInputLetter_Click(object sender, EventArgs e)
        {
            //Invokes the checkletter method to compare inputted char to that of the word
            CheckLetter(char.Parse(tbGuessedLetter.Text));

            //Redraws 
            DrawWord(g);
        }
    }
}

Answer 1

在窗体(或任何其他控件)上绘制的正确方法是通过调用使其无效

Invalidate();

你会这样做而不是 btnInputLetter_Click 中的 DrawWord(g)

然后系统会调用窗体的paint事件。此事件有一个参数，其中包含您应该用于绘画的 Graphics 对象。

所有这些总结起来是这样的:

private void Form1_Paint(object sender, PaintEventArgs e)
{
    DrawWord(e.Graphics);
}

private void btnInputLetter_Click(object sender, EventArgs e)
{
    //Invokes the checkletter method to compare inputted char to that of the word
    CheckLetter(char.Parse(tbGuessedLetter.Text));

    //Redraws 
    Invalidate();
}