python - 在Python中，如果y==0则执行某事，如果y!=0则执行其他操作

Question

大家。我是一名大学生。而我计算飞镖靶的分数至少有30多个小时。

所以，基本上，我必须将飞镖板分成 20 个不同的角度并赋予它“值”——即 1 到 20。并将其分割为不同的半径。而且，如果 y == 0，我必须做一些事情，如果 y!=0，我必须做其他事情。

哦，你不必阅读所有这些代码。那会浪费你的时间。哈哈。所以，

问题是如果我把 x,y 像 -30.0022.00比python理解22.00为0.00(所以，22.00==0.00)另外，在本例中 x =90.71 且 y = -43.01

我不知道是什么问题，请救救我。非常感谢您阅读这个问题，祝您度过愉快的一天。哈哈

哦，这是我的第一个问题，我不知道如何在这里正确编码。所以如果您不介意，我会将其替换为屏幕截图。

x = float(input())
y = float(input())
if y == 0.00:
    if 0 <= x < 6.3:
        score = 50
    elif 6.3 <= x < 15.9:
        score =25
    elif 15.9 <= x < 97.4:
        score = 6
    elif 97.4 <= x< 107:
        score =18
    elif 107 <= x < 160.4:
        score = 6
    elif 160.4 <= x < 170:
        score = 12
    elif -6.3 <= x < 0:
        score = 50
    elif -15.9 <= x < -6.3:
        score = 25
    elif -97.4 <= x < -15.9:
        score = 16
    elif -107 <= x< -97.4:
        score = 48
    elif -160.4 <= x < -107:
        score = 16
    elif -170 <= x < -160.4:
        score = 32
    else:
        score = 0
print(score)
    
if y != 0:
    import math

    angle = math.atan2(y, x)
    if angle < 0:
        angle= angle + (2)*(math.pi)

    r = ((x ** 2 + y ** 2) ** 0.5)

    if r <= 6.3:
        print(50)
    elif 6.3 < r <= 15.9:
        print(25)
    
    if r > 15.9:
        if angle >= (39 / 20) * math.pi:
            value = 6
        elif angle <= (1 / 20) * math.pi:
            value = 6
        elif (1 / 20) * math.pi < angle <= (3 / 20) * math.pi:
            value = 5
        elif (3 / 20) * math.pi < angle <= (5 / 20) * math.pi:
            value = 4
        elif (5 / 20) * math.pi < angle <= (7 / 20) * math.pi:
            value = 3
        elif (7 / 20) * math.pi < angle <= (9 / 20) * math.pi:
            value = 2
        elif (9 / 20) * math.pi < angle <= (11 / 20) * math.pi:
            value = 1
        elif (11 / 20) * math.pi < angle <= (13 / 20) * math.pi:
            value = 20
        elif (13 / 20) * math.pi < angle <= (15 / 20) * math.pi:
            value = 19
        elif (15 / 20) * math.pi < angle <= (17 / 20) * math.pi:
            value = 18
        elif (17 / 20) * math.pi < angle <= (19 / 20) * math.pi:
            value = 17
        elif (19 / 20) * math.pi < angle <= (21 / 20) * math.pi:
            value = 16
        elif (21 / 20) * math.pi < angle <= (23 / 20) * math.pi:
            value = 15
        elif (23 / 20) * math.pi < angle <= (25 / 20) * math.pi:
            value = 14
        elif (25 / 20) * math.pi < angle <= (27 / 20) * math.pi:
            value = 13
        elif (27 / 20) * math.pi < angle <= (29 / 20) * math.pi:
            value = 12
        elif (29 / 20) * math.pi < angle <= (31 / 20) * math.pi:
            value = 11
        elif (31 / 20) * math.pi < angle <= (33 / 20) * math.pi:
            value = 10
        elif (33 / 20) * math.pi < angle <= (35 / 20) * math.pi:
            value = 9
        elif (35 / 20) * math.pi < angle <= (37 / 20) * math.pi:
            value = 8
        elif (37 / 20) * math.pi < angle <= (39 / 20) * math.pi:
            value = 7
        if 15.9 <= r < 97.4:
            a = 1
        elif 97.4 <= r < 107:
            a = 3
        elif 107 <= r <160.4:
            a = 1
        elif 160.4 <= r < 170:
            a = 2
        else:
            a =0
        print(value * a)

Answer 1

如果“python将22.00理解为0.00”意味着“python尝试打印分数”，那是因为缩进。
当 y==0.0 计算得分后，“print(score)”行应缩进。

    ...
    elif -160.4 <= x < -107:
        score = 16
    elif -170 <= x < -160.4:
        score = 32
    else:
        score = 0
    print(score)

if y != 0:
    import math
    ...