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c# - LINQ FirstOrDefault 测试 null

转载 作者:太空宇宙 更新时间:2023-11-03 21:47:26 25 4
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Word1252_7bit 是一个结构体
KeyInt32

如果找不到值,我如何测试是否为 null?

没有 w.Key == -1 但我不知道测试是否返回值。

最后的调试行抛出异常。

List<Word1252_7bit> Words7bit = GetWord1252_7bit();

Word1252_7bit word1252_7bit ;

word1252_7bit = Words7bit.FirstOrDefault(w => w.Key == 1000);
Debug.WriteLine(word1252_7bit.Key.ToString() + " " + word1252_7bit.Value);

word1252_7bit = Words7bit.FirstOrDefault(w => w.Key == -1);
//if (word1252_7bit == null) Debug.WriteLine("word1252_7bit == null");
Debug.WriteLine( word1252_7bit.Key.ToString() + " " + word1252_7bit.Value ) ;

如果我应该使用 FirstOrDefault 以外的东西,请告诉我。在唯一的 Int32 上寻找速度搜索。

不确定它是否有所不同,但 Key 是唯一的,我使用 Key 来覆盖 GetHashCode(),为了节省空间,Key 实际上是 UInt32 的一部分

public Int32 Key
{
get
{
return (Int32)( pack[0] & ( (1<<25) - 1 ) ) ;
}
}

public struct Word1252_7bit : iWord
{
// this maps 128 values to "Windows-1252"
// this is not ASCII
// this is SQL char 8bit normalized to FormD, remove control chars, remove redactions, and cast to lower - 129 - just have to cheat on 1
private static byte[] Win1252_128to256 = new byte[] {
32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52, 53, 54, 55, 56, 57, 58, 59, 60, 61, 62, 63
, 64, 91, 92, 93, 94, 95, 96, 97, 98, 99,100,101,102,103,104,105,106,107,108,109,110,111,112,113,114,115,116,117,118,119,120,121
,122,123,124,125,126,128,130,131,132,133,134,135,137,139,145,146,147,148,149,150,151,152,153,155,156,160,161,162,163,164,165,166
,167,168,169,170,171,172,173,174,175,176,177,178,179,180,181,182,183,184,185,186,187,188,189,190,191,215,223,230,240,247,248,254 };
private static Encoding win1252 = Encoding.GetEncoding("Windows-1252");
private UInt32[] pack;
public Int32 Key { get { return (Int32)(pack[0] & ((1 << 25) - 1)); } }
public override bool Equals(Object obj)
{
// Check for null values and compare run-time types.
if (obj == null) return false;
if (!(obj is Word1252_7bit)) return false;
Word1252_7bit comp = (Word1252_7bit)obj;
if (comp.pack == null) return false;
if (comp.pack.Count() == 0) return false;
return (comp.Key == this.Key);
}
public override int GetHashCode()
{
return Key;
}
public byte[] Bytes
{
get
{
byte b;
List<byte> bytes = new List<byte>(((pack.Length - 1) * 4) + 1);

b = (byte)((pack[0] >> 25) & ((1 << 7) - 1));
bytes.Add(Win1252_128to256[b]);

if (pack.Length > 1)
{
UInt32 cur32;
byte bits4 = 0;
byte bits3 = 0;
for (int i = 1; i < pack.Length; i++)
{
cur32 = pack[i];

if ((i-1) % 2 == 0)
{
bits4 = (byte)((cur32 >> 28) & ((1 << 4) - 1));
}
else
{ // pick up that odd i7
bits3 = (Byte)((cur32 >> 28) & ((1 << 3) - 1));
b = (byte)((UInt32)bits3 | ((UInt32)bits4 << 3));
if (b == 0) break;
bytes.Add(Win1252_128to256[b]);
}

b = (byte)(cur32 & ((1 << 7) - 1));
if (b == 0) break;
bytes.Add(Win1252_128to256[b]);

b = (byte)((cur32 >> 7) & ((1 << 7) - 1));
if (b == 0) break;
bytes.Add(Win1252_128to256[b]);

b = (byte)((cur32 >> 14) & ((1 << 7) - 1));
if (b == 0) break;
bytes.Add(Win1252_128to256[b]);

b = (byte)((cur32 >> 21) & ((1 << 7) - 1));
if (b == 0) break;
bytes.Add(Win1252_128to256[b]);

//Debug.WriteLine(win1252.GetString(bytes.ToArray()));
}
}
return bytes.ToArray();
}
}
public String Value
{
get
{
return win1252.GetString(Bytes);
}
}
public Int32 Lenght { get { return Bytes.Count(); } }
public Word1252_7bit(UInt32[] Pack)
{
if(Pack == null) throw new IndexOutOfRangeException();
if (Pack.Length == 0) throw new IndexOutOfRangeException();
pack = Pack;
}
}

最佳答案

FirstOrDefault<T>将返回找到的第一个项目或默认值 T如果没有找到。对于引用类型,这是 null ,但这对于值类型是不同的。例如,整数的默认值为 0 .

您可以使用 default 关键词:

if (word1252_7bit.Equals(default(Word1252_7bit)))
Debug.WriteLine("not found");

注意:您可能必须编写自己对 Equals 的覆盖以获得您期望的结果。

通常,您无法区分未找到的项目和已找到但等于默认值的项目。您可以这样做:

int foundAt = Words7bit.FindIndex(w => w.Key == -1);
if (foundAt == -1)
Debug.WriteLine("not found");
else
word1252_7bit = Words7bit[foundAt];

关于c# - LINQ FirstOrDefault 测试 null,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/16222869/

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