c# - emgu 3.0.0.0 整形后如何获取像素坐标？

Question

我一直在尝试获取坐标，如下所述: How to get coordinates of pixel after shape was rectified?在 Emgu CV 3.0.0 中。我可以使用以下代码扭曲图像(从上面的链接中窃取)

 Image<Bgr, byte> theWarpedImage = new Image<Bgr, byte>(@"C:\myImage.jpg");
        PointF[] srcs = new PointF[4];
        srcs[0] = new PointF(1533, 2393);
        srcs[1] = new PointF(4169, 1817);
        srcs[2] = new PointF(1765, 1177);
        srcs[3] = new PointF(3717, 621);

        PointF[] dsts = new PointF[4];
        dsts[0] = new PointF(0, 0);
        dsts[1] = new PointF(2950, 0);
        dsts[2] = new PointF(0, 2100);
        dsts[3] = new PointF(2950, 2100);

        PointF[] test = new PointF[4];

        Mat mywarpmat = CvInvoke.GetPerspectiveTransform(srcs, dsts);
        Image<Bgr, byte> theWarpedImage2 = new Image<Bgr, byte>(@"C:\myImage.jpg");
        CvInvoke.WarpPerspective(theWarpedImage, theWarpedImage2, mywarpmat, theWarpedImage2.Size, Emgu.CV.CvEnum.Inter.Linear, Emgu.CV.CvEnum.Warp.Default, Emgu.CV.CvEnum.BorderType.Constant, new MCvScalar(0));

但我无法让 Luca Del Tongo 给出的解决方案在 3.0.0.0 版本中工作

你有什么建议吗？

感谢 MIKI:

 var test2=CvInvoke.PerspectiveTransform(srcs, mywarpmat);

有效。

Answer 1

Miki 找到了解决方案。我用过:

var test2=CvInvoke.PerspectiveTransform(srcs, mywarpmat);

这成功了。谢谢三木