python - 如何将 for 循环(字典)的输出从模型检索到 View ？

Question

我有这个模型:

class ModelName(models.Model):
   def my_dict(self):
         for i in range(n):
             …#some code
             context_a = {‘a’: a}
             return context_a

我需要像这样考虑上下文:

from .models import ModelName

class ViewName
    model = ModelName
    template_name = ’template_name.html’

    def context_b(request):
        context_b = ModelName.objects.get(context_a=context_a) #here I want to get context_a as a dictionary and pass it to context_b for further operations. I know that my syntax here is not correct.
        return render(request, self.template_name, context_b)

如果我这样做，我就会得到

Method Not Allowed: /

[18/Nov/2018 12:40:34] "GET / HTTP/1.1" 405 0

我想知道如何正确执行此操作，以及我应该阅读/学习哪些特定资源(文档和/或文章)来理解我的问题。

如果有任何帮助，我将不胜感激。

Answer 1

我认为您没有在这里对基于类的正确 View 进行子类化。您收到的错误是，您正在调用 get 方法，但您提供的 View 不支持该方法。为了简单起见，让我们使用 DetailsView它支持get请求，所以你可以尝试这样:

class YourView(DetailsView):
  template_name = 'template_name.html'
  model = MyModel

  def get_context_data(self, **kwargs):
     context = super(YourView, self).get_context_data(**kwargs)
     context_a = self.object.my_dict()  # here you will get the dictionary from model in view
     # by the way, you can also access the your model object from context via context['object'] and in template via {{ object }}
     return context

并像这样访问模板的字典:

 {% for k, v in object.my_dict.items %}
      {{ k }} - {{ v }}
 {% endfor %}

还有网址

#urls
path('/someview/<int:pk>/', YourView.as_view(), name="your_view"),