python - Monty Hall 问题在切换和不切换时返回 33% 的结果

Question

所以我一直在尝试用 Python 来模拟一个类似于 Monty Hall 问题的问题，我预计转换后会产生 66% 的获胜结果，但事实并非如此。有人可以指出我哪里出了问题吗？我试图根据转换来得出获胜和失败的百分比。任何帮助将不胜感激。

import random

#Ask the user for how many runs
runs = int(input("How many games do you want to simulate?"))
switchwins, nonswitchwins, switchlosses, nonswitchlosses = 0, 0, 0, 0

# Get the random number started with a seed
random.seed()

#run once for user switching and once for user not switching
for swap in True,False:
# Do everything for the number of runs we have
for i in range(runs):

    # Setup the prize locations
    prizes = ['nothing', 'nothing', 'coin']
    # Randomly mix them up
    random.shuffle(prizes)

    #select a random location
    ChoiceA = random.randrange(3)

    # print("Before the prize is revealed, I will show you what is in one of the other hiding places")

    # remove one of the other hiding places which has nothing as a prize and isn't ChoiceA
    for currentlocation, contents in enumerate(prizes):
        if currentlocation != ChoiceA and contents == "nothing":
            showlocation = currentlocation
            # print("There is nothing in this location", showlocation)
            break


    if swap:
        #swap to the other location
        for currentlocation, contents in enumerate(prizes):
            if currentlocation != ChoiceA and contents != showlocation:
                swap_to = currentlocation

        # check if the swapped choice is a win
        if prizes[swap_to] == "coin":
            switchwins +=1
        else: 
            switchlosses +=1
    # when not swapping locations check for win
    else:
        if prizes[ChoiceA] == "coin":
            nonswitchwins +=1
        else: 
            nonswitchlosses +=1

print("This is the number of wins if the user switched", 
round((switchwins/runs)*100,1), "%")

print("This is the number of wins if the user didn't switch", 
round((nonswitchwins/runs)*100,1),"%")

Answer 1

你写了if currentlocation != ChoiceA andcontents != showlocation:，但这不是if currentlocation != ChoiceA and currentlocation != showlocation:吗？