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python - 使用 matplotlib 在 Python 3 中进行康威的生命游戏 - 显示阵型的问题

转载 作者:太空宇宙 更新时间:2023-11-03 21:32:38 26 4
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我目前正在尝试编写生命游戏的 python 3 实现。我的主要目标是显示一个大小为 n 的网格,该网格根据康威规则随机填充。这部分工作正常。

现在我想实现第二种模式,允许您从给定的编队之一开始 - 在我第一次尝试滑翔机时。

这是主函数:

import matplotlib.pyplot as plt
import matplotlib.animation as animation
from gol_functions import *

def main():

# get arguments from input function
arguments = input_arguments()
# set the arguments
gridsize = int(arguments.gridsize)
interval = int(arguments.interval)
formation = arguments.formationflag

# if you want to start with a formation:
if formation:
grid = np.zeros(gridsize*gridsize).reshape(gridsize, gridsize)
add_glider(1, 1, grid)

# else display a randopm grid
else:
grid = randomgrid(gridsize)

fig, ax = plt.subplots()

# colormap: black -> alive, white -> dead
img = ax.imshow(grid, cmap='binary', interpolation='nearest')

# this will be used to save the animation in a later version
ani = animation.FuncAnimation(fig, update, fargs=(img, grid, gridsize,),
frames=10,
interval=interval,
save_count=50)

# remove x and y - axis labels, numbers and ticks
ax.axes.xaxis.set_ticklabels([])
ax.axes.yaxis.set_ticklabels([])
plt.xticks([])
plt.yticks([])

# plot the animated output
plt.show()


if __name__ == '__main__':
main()

这是添加滑翔机的函数:

def add_glider(i, j, grid):
"""adds a glider with top-left cell at (i, j)"""
glider = np.array([[0, 0, 255],
[255, 0, 255],
[0, 255, 255]])

grid[i:i+3, j:j+3] = glider

它在网格 @ 位置 1, 1 处添加了一个滑翔机

这是我的更新函数:

def update(frameNum, img, grid, gridsize):
"""Updates the grid every time it is refreshed"""
newgrid = grid.copy()
for i in range(gridsize):
for j in range(gridsize):
# this formula considers the edge/boundary conditions that appear
# every cell has to have 8 neighbouring cells
# to implement this in a grid of size n we simply fold the 4 edges to each parallel edge
# we'll end up with a cylinder first, then with a geometric shape called torus (google it.)
total = int((grid[i, (j - 1) % gridsize] + grid[i, (j + 1) % gridsize] +
grid[(i - 1) % gridsize, j] + grid[(i + 1) % gridsize, j] +
grid[(i - 1) % gridsize, (j - 1) % gridsize] +
grid[(i - 1) % gridsize, (j + 1) % gridsize] +
grid[(i + 1) % gridsize, (j - 1) % gridsize] + grid[
(i + 1) % gridsize, (j + 1) % gridsize]) / 255)

# apply conway's basic rules of the game of life for each cell
if grid[i, j] == ON:
if (total < 2) or (total > 3):
newgrid[i, j] = OFF
else:
if total == 3:
newgrid[i, j] = ON
# update data
img.set_data(newgrid)
grid[:] = newgrid[:]
return img,

但是,当我使用显示滑翔机的选项运行它时,我看到的只是以下编队......

failedglider_1.png

它很快就会变成这样并变成静态:

failedglider_2.png

...而不是 add_glider 矩阵中看到的实际滑翔机。所以看来程序以某种方式在顶部添加了一个不需要的活细胞。我试图找到它的来源...但找不到。

有人有线索吗?我很感激所有的帮助。提前致谢!

最佳答案

通过对您原始帖子中的代码进行一些小修改,我能够准确地生成您想要的内容。修改后的代码列在底部。第一帧如下图左侧所示。几帧后,它看起来像右边的图像。所以滑翔机似乎工作得很好:)

enter image description here

#!/usr/bin/python
# call with: python3 cgl.py 10 500 1 1

import os
import argparse
import numpy as np
import matplotlib.pyplot as plt
from matplotlib import animation

ON = 255
OFF = 0


def update(frameNum, img, grid, gridsize):
"""Updates the grid every time it is refreshed"""
newgrid = grid.copy()
for i in range(gridsize):
for j in range(gridsize):
# this formula considers the edge/boundary conditions that appear
# every cell has to have 8 neighbouring cells
# to implement this in a grid of size n we simply fold the 4 edges to each parallel edge
# we'll end up with a cylinder first, then with a geometric shape called torus (google it.)
total = int((grid[i, (j - 1) % gridsize] + grid[i, (j + 1) % gridsize] +
grid[(i - 1) % gridsize, j] + grid[(i + 1) % gridsize, j] +
grid[(i - 1) % gridsize, (j - 1) % gridsize] +
grid[(i - 1) % gridsize, (j + 1) % gridsize] +
grid[(i + 1) % gridsize, (j - 1) % gridsize] + grid[
(i + 1) % gridsize, (j + 1) % gridsize]) / 255)

# apply conway's basic rules of the game of life for each cell
if grid[i, j] == ON:
if (total < 2) or (total > 3):
newgrid[i, j] = OFF
else:
if total == 3:
newgrid[i, j] = ON
# update data
grid[:] = newgrid[:]
img.set_data(newgrid)
return img,


def add_glider(i, j, grid):
"""adds a glider with top-left cell at (i, j)"""
glider = np.array([[0, 0, 255],
[255, 0, 255],
[0, 255, 255]])

grid[i:i+3, j:j+3] = glider


def main():
parser = argparse.ArgumentParser(description="Conway's game of life in Python 3")
parser.add_argument('gridsize', type=int, help='Dimension of grid.')
parser.add_argument('interval', type=int, help='Interval.')
parser.add_argument('formationflag', type=bool, help='Predefined formation.')
parser.add_argument('frame', type=int, help='How many frames to animate.')

# get arguments from input function
arguments = parser.parse_args()
# set the arguments
frame = int(arguments.frame)
gridsize = int(arguments.gridsize)
interval = int(arguments.interval)
formation = arguments.formationflag

# if you want to start with a formation:
if formation:
grid = np.zeros(gridsize*gridsize).reshape(gridsize, gridsize)
add_glider(1, 1, grid)

# else display a randopm grid
else:
grid = randomgrid(gridsize)

fig, ax = plt.subplots()

# colormap: black -> alive, white -> dead
img = ax.imshow(grid, cmap='binary', interpolation='nearest')

# # this will be used to save the animation in a later version
ani = animation.FuncAnimation(fig, update, fargs=(img, grid, gridsize,),
frames=frame,
interval=interval,
save_count=50)

# remove x and y - axis labels, numbers and ticks
ax.axes.xaxis.set_ticklabels([])
ax.axes.yaxis.set_ticklabels([])
plt.xticks([])
plt.yticks([])

# plot the animated output
plt.show()

if __name__ == '__main__':
main()
print("DONE")

关于python - 使用 matplotlib 在 Python 3 中进行康威的生命游戏 - 显示阵型的问题,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/53442614/

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