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python - 给定 Python 中前缀表示法的字符串表达式,递归创建二叉树

转载 作者:太空宇宙 更新时间:2023-11-03 21:32:21 26 4
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Representation of LinkedBinaryTree that should be outputted
导入LinkedBinaryTree

def create_expression_tree(prefix_exp_str):

def create_expression_tree_helper(prefix_exp, start_pos):
start_pos += 1
op = ['+', '-', '*', '/']
elem = prefix_exp[start_pos]
if elem == ' ':
elem = prefix_exp[start_pos+1]
start_pos += 1

if elem not in op:
return LinkedBinaryTree.LinkedBinaryTree.Node(int(elem))
else:
left = create_expression_tree_helper(prefix_exp, start_pos)
right = create_expression_tree_helper(prefix_exp, start_pos+2)
return LinkedBinaryTree.LinkedBinaryTree.Node(elem, left, right)

tree = LinkedBinaryTree.LinkedBinaryTree(create_expression_tree_helper(prefix_exp_str, -1))

return tree

tree1 = create_expression_tree('* 2 + - 15 6 4')
for i in tree1.preorder():
print(i.data, end='')

我实现了自己的二叉树类,如下所示。 Preorder() 是 LinkedBinaryTree 的生成器,它按前缀顺序给出树的值。使用这段代码,我输出*2+-151但它应该输出*2+-1564 如果二叉表达式树已正确创建。我知道大于 1 位的数字存在问题,但我不确定如何在不影响运行时的情况下修复它(即使用切片)。我也不确定为什么它省略了一些标记。有任何想法吗? (该实现必须以线性时间运行,并且在我定义的辅助函数中不使用任何附加参数)。

import ArrayQueue

class LinkedBinaryTree:

class Node:
def __init__(self, data, left=None, right=None):
self.data = data
self.parent = None
self.left = left
if (self.left is not None):
self.left.parent = self
self.right = right
if (self.right is not None):
self.right.parent = self

def __init__(self, root=None):
self.root = root
self.size = self.subtree_count(root)

def __len__(self):
return self.size

def is_empty(self):
return len(self) == 0

def subtree_count(self, root):
if (root is None):
return 0
else:
left_count = self.subtree_count(root.left)
right_count = self.subtree_count(root.right)
return 1 + left_count + right_count


def sum(self):
return self.subtree_sum(self.root)

def subtree_sum(self, root):
if (root is None):
return 0
else:
left_sum = self.subtree_sum(root.left)
right_sum = self.subtree_sum(root.right)
return root.data + left_sum + right_sum


def height(self):
return self.subtree_height(self.root)

def subtree_height(self, root):
if (root.left is None and root.right is None):
return 0
elif (root.left is None):
return 1 + self.subtree_height(root.right)
elif (root.right is None):
return 1 + self.subtree_height(root.left)
else:
left_height = self.subtree_height(root.left)
right_height = self.subtree_height(root.right)
return 1 + max(left_height, right_height)


def preorder(self):
yield from self.subtree_preorder(self.root)

def subtree_preorder(self, root):
if(root is None):
return
else:
yield root
yield from self.subtree_preorder(root.left)
yield from self.subtree_preorder(root.right)


def postorder(self):
yield from self.subtree_postorder(self.root)

def subtree_postorder(self, root):
if(root is None):
return
else:
yield from self.subtree_postorder(root.left)
yield from self.subtree_postorder(root.right)
yield root


def inorder(self):
yield from self.subtree_inorder(self.root)

def subtree_inorder(self, root):
if(root is None):
return
else:
yield from self.subtree_inorder(root.left)
yield root
yield from self.subtree_inorder(root.right)


def breadth_first(self):
if (self.is_empty()):
return
line = ArrayQueue.ArrayQueue()
line.enqueue(self.root)
while (line.is_empty() == False):
curr_node = line.dequeue()
yield curr_node
if (curr_node.left is not None):
line.enqueue(curr_node.left)
if (curr_node.right is not None):
line.enqueue(curr_node.right)

def __iter__(self):
for node in self.breadth_first():
yield node.data

我在此处添加了 LinkedBinaryTree 类的代码。广度遍历方法的实现中使用的ArrayQueue类只是一个使用Python列表作为底层数据结构的基本队列。

最佳答案

您的代码存在两个问题:

  • 您逐一处理了字符,但可能存在多位数字(通过将表达式拆分为列表来修复)
  • 您没有考虑到链式运算符表达式可能比标准增量更长的事实(通过向 Node 添加 size 属性来修复

这是新的 Node

class Node:
def __init__(self, data, left=None, right=None):
self.data = data
self.parent = None
self.left = left
if (self.left is not None):
self.left.parent = self
self.right = right
if (self.right is not None):
self.right.parent = self

@property
def size(self):
l = 1
if self.left is not None:
l += self.left.size
if self.right is not None:
l += self.right.size
return l

这是新的树创建者

def create_expression_tree(prefix_exp_str):

expr_lst = prefix_exp_str.split(" ")

op = {'+': None, '-': None, '*': None, '/': None}

def create_expression_tree_helper(prefix_exp, start_pos):
start_pos += 1
elem = prefix_exp[start_pos]

node = None

if elem not in op:
node = LinkedBinaryTree.Node(int(elem))
else:
left = create_expression_tree_helper(prefix_exp, start_pos)
incr = left.size
right = create_expression_tree_helper(prefix_exp, start_pos+incr)
node = LinkedBinaryTree.Node(elem, left, right)

return node

tree = LinkedBinaryTree(create_expression_tree_helper(expr_lst, -1))

return tree

编辑这是一个不需要修改Node类的版本

def create_expression_tree(prefix_exp_str):

expr_lst = prefix_exp_str.split(" ")

op = {'+': None, '-': None, '*': None, '/': None}

def create_expression_tree_helper(prefix_exp, start_pos):
start_pos += 1
elem = prefix_exp[start_pos]

node = None
size = 1

if elem not in op:
node = LinkedBinaryTree.Node(int(elem))
else:
left, left_size = create_expression_tree_helper(prefix_exp, start_pos)
right, right_size = create_expression_tree_helper(prefix_exp, start_pos+left_size)

node = LinkedBinaryTree.Node(elem, left, right)
size += left_size + right_size

return node, size

tree = LinkedBinaryTree(create_expression_tree_helper(expr_lst, -1)[0])

return tree

关于python - 给定 Python 中前缀表示法的字符串表达式,递归创建二叉树,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/53454035/

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