python - 如何在Python中编码掉html和特殊字符？

Question

1543159687.4969957::I think I\u2019ve gotten far enough into my experiment to give an update: Last year, Child of Humanity was free for Blac\u2026 https://t.co/M3HR5fAoFZ"

这就是我得到的结果。我想创建一个正则表达式来用空格替换\u2019 和\u2026 等特殊元素。它们始终以“\u”开头，然后再继续四个字符。

我还想删除 html。它始终以“https://t.co/”开头，并持续 10 个字符。

我已经尝试了下面的代码，但它显然是错误的。

tweet = re.sub("@[\\u].{4}", "", tweet)

Answer 1

那些\u字符只是unicode字符，您无需执行任何操作，因为当您尝试print mystring时它们会自动转换

对于最终的url，你可以这样做:

removed = re.sub(r'http\S*$', '', mystring) # remove the final http string.

>>> removed
'1543159687.4969957::I think I’ve gotten far enough into my experiment to give an update: Last year, Child of Humanity was free for Blac… '