python - 如何找到资源的坐标？

Question

我正在制作一款游戏，我首先制作了一些框架，供我学习和测试游戏中的不同内容。在这个游戏中，我有一个随机生成的图 block map ，其中包含资源泥土、草、水和煤炭。在代码中，还有一些其他不相关的资源，但我想做的是找到游戏中特定资源的坐标。我打算做的是说资源是一堵墙，它下面有一堵墙，旁边的中间墙的纹理将变成一个角 block 。我的问题是我不知道如何找到坐标。有人可以帮助我吗，老实说，我不确定我在做什么，但我正在努力学习。这是我的代码:

import pygame, sys
import Sprites
import random

from pygame.locals import *

pygame.init()


fpsClock = pygame.time.Clock()

cloudx = -200
cloudy = 0

infoObject = pygame.display.Info()

DIRT = 0
GRASS = 1
WATER = 2
COAL = 3
CLOUD = 4
WALL = 5

controls = {
    DIRT : 49,
    GRASS: 50,
    WATER: 51,
    COAL : 52,
    WALL : 53
}

infoObject = pygame.display.Info()

w = infoObject.current_w
h = infoObject.current_h

TILESIZE  = 40
MAPWIDTH  = 15
MAPHEIGHT = 15

WHITE = (255,255,255)
BLACK = (0,0,0)

resources = [DIRT, GRASS, WATER, COAL]

textures =  {
            DIRT  : pygame.image.load('Sprites/Dirt.png'),
            GRASS : pygame.image.load('Sprites/tile130.png'),
            WATER : pygame.image.load('Sprites/Water.png'),
            COAL  : pygame.image.load('Sprites/Coal.png'),
            CLOUD : pygame.image.load('Sprites/Cloud.png'),
            WALL  : pygame.image.load('Sprites/Swall.png')
          }

playerPos = [0,0]

inventory = {
            DIRT   :  0,
            GRASS  :  0,
            WATER  :  0,
            COAL   :  0,
            WALL   :  10,
            }

tilemap = [[DIRT for w in range(MAPWIDTH)] for h in range(MAPHEIGHT)]



DISPLAYSURF = pygame.display.set_mode((MAPWIDTH*TILESIZE,MAPHEIGHT*TILESIZE + 50))

pygame.display.set_caption('M I N E C R A F T -- 2D')
pygame.display.set_icon(pygame.image.load('Sprites/player.png'))

PLAYER = pygame.image.load('Sprites/Player.png').convert_alpha()

for rw in range(MAPHEIGHT):
    for cl in range(MAPWIDTH):
        randomNumber = random.randint(0,15)
        if randomNumber == 0:
            tile = COAL
        elif randomNumber == 1 or randomNumber == 2:
            tile = WATER
        elif randomNumber >= 3 and randomNumber <=7:
            tile = GRASS
        else:
            tile = DIRT

        tilemap[rw][cl] = tile

INVFONT = pygame.font.Font('freesansbold.ttf', 18)

print(tilemap)

while True:

    currentTile = tilemap[playerPos[1]][playerPos[0]]

    DISPLAYSURF.fill(BLACK)

    for event in pygame.event.get():
#        print(event)
        if event.type == QUIT:

            pygame.quit()
            sys.exit()

        elif event.type == KEYDOWN:

            for key in controls:


                if (event.key == controls[key]):

                    if inventory[key] > 0:

                        inventory[key] -=1

                        inventory[currentTile] += 1

                        tilemap[playerPos[1]][playerPos[0]] = key

            if(event.key == K_RIGHT) and playerPos[0] < MAPWIDTH - 1:
                playerPos[0]+=1

            elif(event.key == K_LEFT) and playerPos[0] > 0:
                playerPos[0]-=1

            elif(event.key == K_DOWN) and playerPos[1] < MAPHEIGHT - 1:
                playerPos[1]+=1

            elif(event.key == K_UP) and playerPos[1] > 0:
                playerPos[1]-=1

            if event.key == K_SPACE:
                currentTile = tilemap[playerPos[1]][playerPos[0]]
                inventory[currentTile] += 1
                tilemap[playerPos[1]][playerPos[0]] = DIRT

    for row in range(MAPHEIGHT):
        for column in range(MAPWIDTH):
                DISPLAYSURF.blit(textures[tilemap[row][column]],(column*TILESIZE, row*TILESIZE, TILESIZE, TILESIZE))
                DISPLAYSURF.blit(PLAYER,(playerPos[0]*TILESIZE,playerPos[1]*TILESIZE))


    DISPLAYSURF.blit(textures[CLOUD].convert_alpha(),(cloudx,cloudy))
    cloudx +=1

    if cloudx > MAPWIDTH*TILESIZE:
        cloudy = random.randint(0, MAPHEIGHT*TILESIZE)
        cloudx = -200


    placePosition = 10
    for item in resources:
        DISPLAYSURF.blit(textures[item],(placePosition, MAPHEIGHT*TILESIZE+10))
        placePosition+=50
        textObj = INVFONT.render(str(inventory[item]), True, WHITE, BLACK)
        DISPLAYSURF.blit(textObj,(placePosition, MAPHEIGHT*TILESIZE+20))
        placePosition += 50

    pygame.display.update()
    fpsClock.tick(24)

    for x in range(MAPWIDTH):
        for y in range(MAPHEIGHT):
            if tilemap[x][y] == WALL:
                pos = tilemap[x][y]
                if tilemap[pos[1]][pos[0]-1] == WALL:
                    print('I DID IT')

    pygame.display.update()

编辑:我当前的代码已更新，添加的部分在最后

Answer 1

如果你想找到特定图 block 的坐标，那么这将需要一些工作。也就是说，您的程序必须搜索每个图 block 并进行比较以查看它是否是WALL图 block 。即

for x in range(MAPWIDTH):
    for y in range(MAPHEIGHT):
        if tilemap[y][x] == WALL:
            # Do something here...

但是，这是极其效率低下的。虽然当你的 map 只有 15 x 15 时这可能不是问题，但如果你扩大 map ，它就会开始消耗你的性能。

仅检查屏幕上显示的区域可能是更明智的做法。毕竟，您只是想弄清楚图 block 应该如何显示 - 否则并不重要。

for x in range(30): # Replace with whatever number of tiles is displayed horizontally on the screen, times two
    for y in range(30): # Do the same here
        if tilemap[y][x] == WALL:
            # Do something here

不过，请注意 - 如果这仅用于显示，则更好的解决方案是定义多个 WALL 图 block 。您可以通过创建像 WALL_UPPER_RIGHT 这样的常量来做到这一点，但以列表的形式制作它会是一个更好的主意。

WALL_TILES = [[5, 6, 7],
              [8, 9, 10],
              [11, 12, 13]]
# WALL_TILES is a 2D list in the format:
# upper left    upper middle    upper right
# middle left  middle middle   middle right
# lower left    lower middle    lower right

然后，您可以使用 WALL_TILES[0][2] 来解决类似 WALL_UPPER_RIGHT 的问题。当您有多个墙砖时，只要墙砖或其旁边的砖发生变化，您只需更改墙砖的类型即可。

添加:

要检查周围的瓷砖是否也是墙砖，您可以检查 x 位置和 y 位置都在中心瓷砖 1 以内的瓷砖。例如，您可以检查tilemap[pos[1]][pos[0]-1]。