Python sendmail - 将 header 添加到 MimeMultipart 以避免隐藏所有收件人

Question

我有一个代码可以发送一封使用 HTML 进行模板化的电子邮件。所有收件人都会收到邮件，但都是密件抄送。

def sendMail(to, cc, bcc, template, bodyParams, subjectParams):
    global connection
    if not testCurrentConnection(connection):
        connect(currentConnectionName)
    msg = MIMEMultipart('alternative')
    subject, fromEmail, body = templateController.readTemplate(template)
    header = 'To: ' + to + '\n' + 'Cc: ' + cc + 'From: ' + fromEmail + '\n' + 'Subject: ' + subject + '\n'
    msg.attach(MIMEText(header, 'text'))
    if subjectParams:
        msg['Subject'] = templateController.replaceTextWithParams(subject, subjectParams)
    else:
        msg['Subject'] = subject
    if bodyParams:
        msg['Body'] = templateController.replaceTextWithParams(body, bodyParams)
    else:
        msg['Body'] = body

    msg['From'] = fromEmail
    msg['To'] = to
    msg['Cc'] = cc
    # no need to specify bcc here

    msg.attach(MIMEText(msg['Body'], 'html'))
    connection.sendmail(msg['From'], [msg['To'], msg['Cc'], bcc], msg.as_string())
    del msg

我这样调用该函数:

smtpController.sendMail("myMail@gmail.com", "ccMail@gmail.com", "", "email.html", None, None)

(最后两个变量实际上是一个带有键值映射的字典，用于填充 HTML，但如果没有它们，问题也会重现)

我读到我需要在消息中添加 header 以防止出现这种情况，但由于某种原因，添加 header 不会改变任何内容(上述代码中的第 7-8 行)。
我错过了什么？

Answer 1

好吧，我不知道它有何不同，但我通过移动 msg['To'] = to 和 msg['Cc'] = cc< 来修复它 向上，位于 Subject 和 Body 之前。我完全删除了标题。

def sendMail(to, cc, bcc, template, bodyParams, subjectParams):
    global connection
    if not testCurrentConnection(connection):
        connect(currentConnectionName)
    subject, fromEmail, body = templateController.readTemplate(template)
    msg = MIMEMultipart('alternative')
    msg['From'] = fromEmail
    msg['To'] = to
    msg['Cc'] = cc
    if subjectParams:
        msg['Subject'] = templateController.replaceTextWithParams(subject, subjectParams)
    else:
        msg['Subject'] = subject
    if bodyParams:
        msg['Body'] = templateController.replaceTextWithParams(body, bodyParams)
    else:
        msg['Body'] = body

    msg.attach(MIMEText(msg['Body'], 'html'))
    connection.sendmail(msg['From'], to.split(',') + cc.split(',') + bcc.split(','), msg.as_string())
    del msg