c# - XPath : Get nodes where child node contains an attributeHow to select node that have and attribute and whose parent have another attribute in c#

Question

我有一个类似的 XML

<Validation>
    <Presentation>
        <Slide Tag = "Pippo">
            <Shape Name = "Pluto"/>
        </Slide>
        <Shape Name = "Pluto"/>
    </Presentation>
</Validation>

我怎样才能改进这个 C# 代码片段

 String xPath = string.Format("/Validation/Presentation/Shape[@Name='{0}'][1]", "Pluto");
 XmlNode node = doc.DocumentElement.SelectSingleNode(xPath);

只获取属性名称为“Pluto”的形状节点，其父节点的属性标签为“Pippo”？

Answer 1

您可以使用以下 Xpath 字符串获取此节点:

string xPath = string.Format("//*[@Tag='{0}']/Shape[@Name='{1}']", "Pippo","Pluto");
XmlNode node = doc.DocumentElement.SelectSingleNode(xPath);