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python - 如何根据osmnx上的一些 "manually chosen"节点绘制路径?

转载 作者:太空宇宙 更新时间:2023-11-03 21:20:12 26 4
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我想在 osmnx map 上绘制一条路线。当我尝试手动创建路线时,它不起作用。

import networkx as nx
import osmnx as ox
import requests
import matplotlib.cm as cm
import matplotlib.colors as colors
location_point = (50.345559621674596, 7.576892382877531)
G = ox.graph_from_point(location_point, distance=500,
distance_type='network', network_type='walk')
origin_node = ox.get_nearest_node(G, location_point)
destination_node = list(G.nodes())[-1]
fig, ax = ox.plot_graph(G)
G=nx.convert_node_labels_to_integers(G)
route = [3 ,1 ,41 ,40 ,98 ,62 ,67 ,107 ,94 ,83 ,39 ]
ox.plot_route_folium(G,route)

我期望一张带有彩色路线的 map ,但我得到了这个错误。

    ---------------------------------------------------------------------------
IndexError Traceback (most recent call last)
<ipython-input-9-11235dc07ef4> in <module>()
----> 1 ox.plot_route_folium(G,route)

~\Anaconda3\lib\site-packages\osmnx\plot.py in plot_route_folium(G, route, route_map, popup_attribute, tiles, zoom, fit_bounds, route_color, route_width, route_opacity)
907 gdf_edges = graph_to_gdfs(G, nodes=False, fill_edge_geometry=True)
908 route_nodes = list(zip(route[:-1], route[1:]))
--> 909 index = [gdf_edges[(gdf_edges['u']==u) & (gdf_edges['v']==v)].index[0] for u, v in route_nodes]
910 gdf_route_edges = gdf_edges.loc[index]
911

~\Anaconda3\lib\site-packages\osmnx\plot.py in <listcomp>(.0)
907 gdf_edges = graph_to_gdfs(G, nodes=False, fill_edge_geometry=True)
908 route_nodes = list(zip(route[:-1], route[1:]))
--> 909 index = [gdf_edges[(gdf_edges['u']==u) & (gdf_edges['v']==v)].index[0] for u, v in route_nodes]
910 gdf_route_edges = gdf_edges.loc[index]
911

~\Anaconda3\lib\site-packages\pandas\core\indexes\base.py in __getitem__(self, key)
2082
2083 if is_scalar(key):
-> 2084 return getitem(key)
2085
2086 if isinstance(key, slice):

IndexError: index 0 is out of bounds for axis 0 with size 0

如果我尝试通过最短路径算法找到一条路线并将其在 map 上可视化,那么效果很好。但我想绘制这条具体路线

最佳答案

OSMnx 使用节点的 OSMID。当您运行 G=nx.convert_node_labels_to_integers(G) 时,您将覆盖这些 OSMID。但是,您并没有在图边的 uv 属性中覆盖它们,这些属性标识边的端点(使用 OSMID)。

关于python - 如何根据osmnx上的一些 "manually chosen"节点绘制路径?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/54348528/

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