python - 如何在Python中的另一个循环中正确编写一个for循环？

Question

我正在尝试对现有的 for 循环进行尽可能多的迭代，这样我就不必手动执行此操作。我的嵌套循环根据医生和医院的喜好来匹配他们。这里get函数中的1.0指的是等级1。

这是我到目前为止想到的(代码中的 # 解释得更多):

def hospital_ranking_of_doctor(hospital, doctor):
    return ranking_by_hospitals2[hospital][doctor]

#free_doctors is currently a range (0,10)
for i in range(len(free_doctors)):
    #Make a dictionary with name Round_(i+1) (To start at Round_1)
    Round_(str(i+1)) = {}
    #Start off with same values as last round, this action should not be performed in the first round
    Round_(str(i+1)).update(Round_(str(i))
    Round_(str(i+1))_values = list(Round_(str(i+1)).values())
    for Doctor_ in ranking_by_doctors:
        favored_hospital = ranking_by_doctors[Doctor_].get(1.0 + i) #Hospitals are ranked from 1.0 - 10.0, need 1.0 or would start at 0 and get error
        favored_hospital_doctor = Doctor_
#If the hospital and doctor have not been assigned to a match before, assign the current hospital to the current doctor
        if favored_hospital not in Round_(str(i+1)) and favored_hospital_doctor not in Round_(str(i+1))_values:
                Round_(str(i+1))[favored_hospital] = Doctor_
#If the doctor has been assigned to a match before, continue with the next doctor
    elif favored_hospital_doctor in Round_(str(i+1))_values:
        continue
#If the hospital has been assigned to a match before, check if the previously assigned doctor is ranked higher (e.g 2.0 instead of 1.0)
#When this is indeed the case, the hospital prefers the new doctor over the old doctor, so assign the new doctor as its match    
    else:
        previously_assigned_doctor = Round_(str(i+1))[favored_hospital]
        if hospital_ranking_of_doctor(favored_hospital, previously_assigned_doctor) > hospital_ranking_of_doctor(favored_hospital, Doctor_):
            Round_(str(i+1)[favored_hospital] = Doctor_
Matches['Round_'str(i+1)] = Round_(str(i+1))
Matches

免费医生:

['Doctor_10', 'Doctor_6', 'Doctor_5', 'Doctor_9', 'Doctor_1', 'Doctor_4', 'Doctor_3', 'Doctor_7', 'Doctor_2', 'Doctor_8']

嵌套的 for 循环可以工作，但是循环遍历循环会出现语法错误。在所有显示 (str(i+1)) 的地方，我都会在新的命令代码中手动写入前面的数字(因此 1 代表第 1 轮，get(1.0)，并且2 使用 get(2.0) 进行第 2 轮。这对于 10 名医生和 10 家医院的数据集是可行的。但是，我想增加该数据集的大小，然后手动执行此操作变得不可持续。所以我想编写一个循环来自动为我执行此操作，然后字典 Matches 应该显示所有十轮以及在这些轮中获得的比赛。

比使用range(len(free_doctors))更好的是，如果循环一直持续到所有医生和医院都匹配完毕。

Answer 1

看来您正在努力解决“稳定婚姻”问题。不再是丈夫和妻子无法“交易”，而是有医生和医院，但结构是一样的:学生和学校等。

https://gist.github.com/joyrexus/9967709是 Google 首次推出的“稳定婚姻”Python，它可能会满足您的需求。