c# - 从字符串中提取键值对

Question

我有以下字符串:

string myString = "{'gridObject':'[1,2,3,4],[5,6,7,8]'}";

我如何将它处理成一个对象，以便我可以这样做:

charts[0]     //=> [1,2,3,4]
charts[0][1]  //=> 2

如果我能把它转换成这个对象，那就更好了:

public class gridObject {

    public int datarow   {get; set;}
    public int datacol   {get; set;}
    public int datasizex {get; set;}
    public int datasizey {get; set;}

}

Answer 1

这就是我会做的。

首先创建你的类，

public class GridObject
{
    public int datarow { get; set; }
    public int datacol { get; set; }
    public int datasizex { get; set; }
    public int datasizey { get; set; }
}

public class GridObjectCollection
{
    public GridObject[] GridObjects { get; set; }
}

然后，看看你需要什么 JSON，序列化一次:(JsonConvert 是 Json.NET 的一部分，你可以用 NuGet 得到它)

GridObjectCollection gridObjects = new GridObjectCollection();
gridObjects.GridObjects = new GridObject[]
{
    new GridObject() { datacol = 1, datarow = 2, datasizex = 3, datasizey = 4 },
    new GridObject() { datacol = 5, datarow = 6, datasizex = 7, datasizey = 8 }
};

Console.WriteLine
(
    JsonConvert.SerializeObject
    (
        gridObjects,
        new JsonSerializerSettings() { Formatting = Formatting.Indented }
    )
);

在这里您可以看到反序列化时将生成这些类的有效 JSON 内容如下:

{
  "GridObjects": [
    {
      "datarow": 2,
      "datacol": 1,
      "datasizex": 3,
      "datasizey": 4
    },
    {
      "datarow": 6,
      "datacol": 5,
      "datasizex": 7,
      "datasizey": 8
    }
  ]
}

然后，尝试反序列化以确保:

var f = JsonConvert.DeserializeObject<GridObjectCollection>
(
    "{'GridObjects':[{'datarow':2,'datacol':1,'datasizex':3,'datasizey':4},{'datarow':6,'datacol':5,'datasizex':7,'datasizey':8}]}"
);