python - 使用返回值作为变量而不调用整个函数

Question

这是我的目标:

创建一个脚本，接受 2 个 CSV 文件并返回仅包含差异的第三个 CSV 文件。

我使用的是 Python 3.7.2。

这是我的代码:

def findFile1():
    filename =  ## prompts the user to select a .csv file.
    with open(filename, 'r') as t1:
        fileone = t1.readlines()
    return fileone


def findFile2():
    filename =  ## prompts the user to select another .csv file.
    with open(filename, 'r') as t2:
        filetwo = t2.readlines()
    return filetwo


def saveFile():
    filename =  ## prompts the user to name and choose a location to save a new .csv file.
    fileone = findFile1() ##Here I would just like to readlines from the first CSV file. Not run the whole script again. 
    filetwo = findFile2() ##Here I would just like to readlines from the second CSV file. Not run the whole script again.
    with open(filename, 'w') as outFile:
        for line in filetwo:
            if line not in fileone:
                outFile.write(line)

我想要的只是使用前两个函数的返回值，而不是再次调用整个函数。

更新:我能够通过 Charles Duffy 的建议“导入 functools 并将 @functools.lru_cache() 行放在函数上方，并且所有 future 的调用都将重用先前调用的结果”来解决此问题

Answer 1

更新:我能够通过 Charles Duffy 的建议“导入 functools 并将 @functools.lru_cache() 行放在函数上方，并且所有将来的调用都将重用先前调用的结果”来解决此问题