python - 这是 python 中 `in` 关键字的正确使用吗？

Question

我试图通过使用 if/in 检查来制作一个非常基本的刽子手游戏，但是，代码没有响应玩家输入的更改。由于这是我第一次使用 in 关键字，我想问一下这是否正确。

我尝试了其他一些方法，例如字符串查找和单独将字母制成字符串(这很困惑)，if/in似乎是最有效的方法完成任务。如果还有其他方法，请告诉我。

#put word into here, as a string :)

print("Welcome to Hangman")
word = ["a", "v", "a", "c" "a", "d", "o"]

wordLength = len(word) + 1
lives = wordLength * 2

print("lives:", lives)
print("Letters in word", wordLength)

guess = input("h")

while lives != 0:
    if guess in word:
        print("YES!")
        print(guess)
        index = word.index(guess)
        print(index)
    else:
        print("Wrong!")
        lives - 1
    pass
pass


while lives == 0:
    print("falied! try again")
pass

理想的结果是当输入与上述字符串中的字母匹配时，控制台将打印“YES!”和这封信，或者如果不打印“错误”并夺走一条生命。

Answer 1

请检查此代码是否适合您。我稍微修改了一下，添加了一些条件。

#put word into here, as a string :)

print("Welcome to Hangman")
word = ["a", "v", "a", "c", "a", "d", "o"]

wordLength = len(word) + 1
lives = wordLength * 2

print("lives:", lives)
print("Letters in word", wordLength)

guess = input("Enter the letter : ")

while lives != 0:
    if guess in word:
        print("YES!")
        print(guess)
        index = word.index(guess)
        #print("Index = ",index)
        del word[index]
    else:
        print("Wrong!")
        lives -=1
    print("lives:", lives)

    if len(word)==0 and lives > 0:
        print("Success!!")
        break
    guess = input("Enter the letter : ")



if lives == 0:
    print("falied! try again")