python - 如何按照列表的顺序重命名文件夹中的多个文件

Question

我有几个包含许多文件的文件夹:

Folder
|---Folder1
|      |------File1, File2,...
|
|---Folder2
       |------File3, File4,...

我还有my_list = [rename1, rename2, rename3, rename4]

我正在尝试完全按照 my_list 的顺序和名称重命名 [File1, File2, File3, File4]。

我已经尝试过这个:

list_of_dirs = [path_to_file1, path_to_file2, path_to_file3, path_to_file4]
my_list = [rename1, rename2, rename3, rename4]
for i in list_of_dirs:
    os.rename(i, 'path_to_saving_directory' + str(j for j in my_list))

但这会创建一个生成器对象，并包含与所需的[rename1、rename2、rename3、rename4]不匹配的文件。

Answer 1

您正在尝试迭代两个列表。

以下是一个相当标准的模式。您仍然希望使用 os.rename 来实际重命名文件，而不是 print 。

>>> list_of_paths = ['path1', 'path2', 'path3', 'path4']
>>> new_names = ['rename1', 'rename2', 'rename3', 'rename4']
>>> 
>>> 
>>> for original_path, new_name in zip(list_of_paths, new_names):
...   print(f"need to rename file at {original_path} to {new_name}")
... 
need to rename file at path1 to rename1
need to rename file at path2 to rename2
need to rename file at path3 to rename3
need to rename file at path4 to rename4
>>>