python - 如何设置python中字符的二进制形式显示的字节数？

Question

我希望能够将字符串中每个字符显示的字节数设置为 6。这里，字符串是 jJ，我得到的输出为 1000111001 。 J 给出 1001，我希望它显示 001001。

a = ['A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P','Q','R','S','T','U','V','W','X','Y','Z','a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z','0','1','2','3','4','5','6','7','8','9','+','/']
def mapFirst(string):
   return ''.join(bin(ord(chr(a.index(c)))) for c in string).replace('0b','')

def main():
    k = 'jJ'
    print(mapFirst(k))

if __name__ == "__main__":
  main()

Answer 1

更改:

return ''.join(bin(ord(chr(a.index(c)))) for c in string).replace('0b','')

与:

return ''.join(str(bin(ord(chr(a.index(c))))).replace('0b','').zfill(6) for c in string)

您正在寻找的函数是zfill(width)

<小时/>

注意:为了便于阅读，我建议您将该行拆分为多行。