c# - 如何获取字符串的特定部分并将它们分配给 C# 中的变量？

Question

将这样的字符串传递给后面的代码:

0,-1|1,-1|2,-1|3,-1|4,-1|5,-1|6,-1|7,-1|8,-1

我需要能够为每个“|”的“，”符号前后分配值字符串中存在的符号，分为分隔的变量，“line”表示第一个值(在“,”之前)，“group”表示下一个值(在“,”之后)。

现在我正在尝试这个，但是我在从 string[] 转换为 string 时遇到了一些问题。

public static string GuardarGrupos(string parametro){


    var data = parametro.Split(Convert.ToChar("|"));

    var datos = "";
    string[] linea;
    var grupo = "";

    //Iterate through each of the letters
    foreach (var check in data)
    {

        datos = data[0];
        linea = data[0].Split(Convert.ToChar(","));

    }

    return linea;
}

知道我怎样才能做到这一点吗？

Answer 1

制作 class或 struct坚持你的值(value)观:

public class DataObject
{
   public string X {get; set;}

   public string Y {get; set;}
}

返回 List<T>类型 DataObject

public static List<DataObject> GuardarGrupos(string parametro){
    //List to return
    List<DataObject> returnList = new List<DataObject>();

    //Split the string on pipe to get each set of values
    var data = parametro.Split('|'); //No need to do a convert.char(), 
    //String.Split has an overload that takes a character, use single quotes for character

    //Iterate through each of the letters
    foreach (var check in data)
    {
       //Split on comma to get the individual values
       string[] values = check.Split(',');
       DataObject do = new DataObject()
       {
          X = values[0];
          Y = values[1];
       };
       returnList.Add(do);
    }

    return returnList;
}

一旦你有了 List<DataObject> ，您可以使用 linq 形成行和组和 string.Join :

List<DataObject> myList = GuardarGrupos("0,-1|1,-1|2,-1|3,-1|4,-1|5,-1|6,-1|7,-1|8,-1");
string line = string.Join(",", myList.Select(x => x.X);
string group = string.Join(",", myList.Select(y => y.Y);