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c# - RX : How to bind an IObservable to a property (ReactiveUI)
转载 作者：太空宇宙 更新时间：2023-11-03 20:50:35 24 4
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我有课MyClient用IObservable<IStatus> (Client.StatusStream())。现在我想合并 ReactiveX和 ReactiveUI .但是文档没有提供任何如何一起使用它们的示例。

到目前为止，我已经尝试了一些扩展方法(例如 .ToProperty)，但它们不起作用。

public partial class MainWindow : ReactiveWindow<AppViewModel>
{
    public MainWindow()
    {
        InitializeComponent();
        ViewModel = App.Container.GetInstance<AppViewModel>();
        this.WhenActivated(r =>
            {
                this.OneWayBind(ViewModel, viewModel => viewModel.Status.AoiStatus, view => view.StatusTxtbl.Text).DisposeWith(r);
                this.OneWayBind(ViewModel, viewModel => viewModel.Status.OperationMode, view => view.OpModeTxtbl.Text).DisposeWith(r);
                this.OneWayBind(ViewModel, viewModel => viewModel.Status.TestPlan, view => view.TestplanTxtbl.Text).DisposeWith(r);
            });
    }

    private async void ButtonGetStatus_OnClick(object sender, RoutedEventArgs e)
    {
        // the manual mode to get the actual status information
        var status = await ViewModel.Client.GetStatusAsync();
        ViewModel.Status = status;
    }
}

public class AppViewModel : ReactiveObject
{
    private IStatus _Status;
    public IStatus Status
    {
        get => _Status;
        set => this.RaiseAndSetIfChanged(ref _Status, value);
    }

    public MyClient Client { get; }

    public AppViewModel(MyClient client)
    {
        Client = client;
        // automatically pushes every new status information
        Client.StatusStream(); // <- How to get the data out there?
    }
}

信息

要通知有关新更新的 gui，必须使用 ObserveOnDispatcher , 请参阅 https://stackoverflow.com/a/55811495/6229375

最佳答案

将 Status 定义为 output property :

public class AppViewModel : ReactiveObject
{
    private readonly ObservableAsPropertyHelper<IStatus> _status;
    public string Status => _status.Value;

    public MyClient Client { get; }

    public AppViewModel(MyClient client)
    {
        Client = client;
        Client.StatusStream().ToProperty(this, x => x.Status, out _status);
    }
}

关于c# - RX : How to bind an IObservable<object> to a property (ReactiveUI)，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/55807509/

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