python - 比较在Python中两个字典的相同索引处找到的键值对

Question

我想比较两个字典的键值对。比较的方式是，将第一个字典的第一项与第二个字典的第一项进行比较，将第二项与第二项进行比较，如下所示。

字典的结构是:

dep_feats = {0: {'Gender': {'Masc'}, 'Number': {'Sing'}, 'Person': {'3'}}, 1: {}, 2: {'Number': {'Sing'}, 'Person': {'3'}}, 3: {'Gender': {'Masc'}, 'Number': {'Sing'}, 'Person': {'3'}, 'Tens': {'Past'}, 'Voice': {'Act'}}, 4: {}}

和

head_feats = {0: {'Gender': {'Masc'}, 'Number': {'Sing'}, 'Person': {'3'}, 'Tens': {'Past'}, 'Voice': {'Act'}}, 1: {'Number': {'Sing'}, 'Person': {'3'}}, 2: {'Gender': {'Masc'}, 'Number': {'Sing'}, 'Person': {'3'}, 'Tens': {'Past'}, 'Voice': {'Act'}}, 3: {}, 4: {'Gender': {'Masc'}, 'Number': {'Sing'}, 'Person': {'3'}, 'Tens': {'Past'}, 'Voice': {'Act'}}}

for i in range(len(dep_feats)):
    for j in range(len(head_feats)):
        if i == j:
            if dep_feats[i].items() == head_feats[i].items():
                print(dep_feats[i].items())

Answer 1

这可以通过zip()来完成

for dep, head in zip(dep_feats.items(), head_feats.items()):
    if dep == head:
        print(dep)