python - 即使存在函数，Python 中也未定义全局名称帮助器

Question

这个问题已经有答案了:

How can I call a function within a class? (2 个回答)

已关闭 3 年前。

我正在解决这个问题https://leetcode.com/problems/climbing-stairs并收到错误“全局名称助手未定义”。但它是在类中定义的吗？

class Solution(object):
    def climbStairs(self, n, ):
        """
        :type n: int
        :rtype: int
        """

        return helper(0, n)

    def helper(self, curr, n):
        if (curr > n):
            return 0

        if (curr == n):
            return 1

        return helper(curr + 1, n) + helper(curr + 2, n)

Answer 1

您缺少 helper 的“self”参数，即用 self.helper() 替换 helper() 应该可以工作。

class Solution(object):
    def climbStairs(self, n, ):
        """
        :type n: int
        :rtype: int
        """

        return self.helper(0, n)

    def helper(self, curr, n):
        if (curr > n):
            return 0

        if (curr == n):
            return 1

        return self.helper(curr + 1, n) + self.helper(curr + 2, n)