python - 我该如何解决与折线的二维坐标相关的问题

Question

我有一个折线坐标的字符串输入:

 (1,2)(2,3)(4,5)(8,9)

我有功能:-

def distance(p1,p2):

如何将值 (1,2) 和 (2,3) 发送到 p1 和 p2 等等并计算每个点之间的距离？

Answer 1

您收集输入(这是一个字符串):

in_coord = input('Please enter coordinates in format "x y x y": ')

然后将输入转换为集合:

in_conv = [int(i) for i in in_coord if i != ' ']
p_list = []
for e in range(0, len(in_conv), 2):
    p_list.append((in_conv[e], in_conv[e+1]))

现在将它们发送到您的函数:

def distance(p1, p2):
    print(f'Result of {p1} and {p2}')

for i in range(0, len(p_list), 2):
    distance(p_list[i], p_list[i+1])

所以在实践中它看起来像这样:

>>> in_coord = input('Please enter coordinates in format "x y x y": ')
Please enter coordinates in format "x y x y": 1 2 2 3 4 5 8 9
>>> in_conv = [int(i) for i in in_coord if i != ' ']
>>> p_list = []
>>> for e in range(0, len(in_conv), 2):
...     p_list.append((in_conv[e], in_conv[e+1]))
... 
>>> def distance(p1, p2):
...     print(f'Result of {p1} and {p2}')
... 
>>> for i in range(0, len(p_list), 2):
...     distance(p_list[i], p_list[i+1])
... 
Result of (1, 2) and (2, 3)
Result of (4, 5) and (8, 9)

<小时/>

如果您想使用原始字符串，请将其替换为生成 p_list:

x = '(1,2)(2,3)(4,5)(8,9)'
p_list = []
for i in x:
    try:
        p_list.append(int(i))
    except ValueError:
        pass