python lru_cache显式修改

Question

假设我有以下功能:

@lru_cache(maxsize=None)
def very_expensive_function(arg):
    ...

在运行时期间，我可以计算某些参数的very_expense_function(不调用它)的结果。是否可以将这些结果注入(inject)到缓存中，而不需要very_expense_function 自己计算出来？

Answer 1

ring还提供修改功能。

import ring

@ring.lru()
def very_expensive_function(arg):
    pass

v = very_expensive_function(1)
very_expensive_function.delete(1)  # delete cache for 1

# other functions 
v = very_expensive_function.execute(1)  # run without any cache function
v = very_expensive_function.get(1)  # get only if cache exists
v = very_expensive_function.update(1)  # force to update
very_expensive_function.set(x, 1) # override cache value without running

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