python - 如何以字符串形式获取 XML 元素的内容？

Question

考虑这个 XML 示例:

<data>
    <items>
        <item name="item1">item1pre <bold>ok!</bold> item1post</item>
        <item name="item2">item2</item>
    </items>
</data>

我正在寻找一种方法来获得以下结果:

“item1pre **好的!** item1post”

我想将item1的所有内容作为字符串“item1pre <'bold> ok!<'/bold> item1post”，然后将“<'bold>”和“<'/bold>”替换为“* *”，但我不知道如何得到它。

Answer 1

xml="""
<data>
    <items>
        <item name="item1">item1pre<bold>ok!</bold>item1post</item>
        <item name="item2">item2</item>
    </items>
</data> 
"""

import xml.etree.ElementTree as ET
# python included module

def cleaned_strings_from_xml(xml_str, tag='item'):
    """
    finds all items of type tag from xml-string

    :param xml_str: valid xml structure as string
    :param tag: tag to search inside the xml
    :returns: list of all texts of 'tag'-items
    """
    strings = []
    root = ET.fromstring(xml)
    for item in root.iter(tag):
        item_str = ET.tostring(item).decode('utf-8')
        item_str = item_str.replace('<bold>', ' **').replace('</bold>', ' **')
        strings.append(ET.fromstring(item_str).text)
    return strings

print(cleaned_strings_from_xml(xml))