python - 这是登录 Flask 的正确方式吗？

Question

我编写了一个 Flask 应用程序，如下所示:

import logging
from flask import Flask, jsonify
from mongo import Mongo
app = Flask(__name__)
app.config.from_object("config.ProductionConfig")


# routes to a particular change and patch number
@app.route("/<project>/")
def home(project):

    app.logger.info('testing info log')
    Mongo_obj = Mongo(ip=app.config["DB_HOST"], port=app.config["DB_PORT"],
                      username=app.config["DB_USERNAME"],

.....................
if __name__ == '__main__':
    app.run(host = '0.0.0.0', port = '5000')

现在，我面临的问题是，当我查看 Flask 应用程序的日志时，我看到的只是以下内容:

* Serving Flask app "service" (lazy loading)
 * Environment: production
   WARNING: This is a development server. Do not use it in a production deployment.
   Use a production WSGI server instead.
 * Debug mode: off
 * Running on http://0.0.0.0:5000/ (Press CTRL+C to quit)
172.16.40.189 - - [01/Oct/2019 14:44:29] "GET /abc HTTP/1.1" 200 -
172.16.11.231 - - [01/Oct/2019 14:44:29] "GET /abc HTTP/1.1" 200 -
............

是否需要执行某些特定操作才能查看日志消息？我需要在 Debug模式下运行 Flask 应用程序吗？

Answer 1

这就是我在应用程序中设置日志级别的方式。我使用 create_app 函数创建一个包含错误处理日志记录和其他必要配置的 Flask 应用程序。这是片段:

from flask import Flask
import logging


def create_app(test_config=None):
    # create and configure the app
    app = Flask(__name__)
    app.logger.setLevel(logging.ERROR)

    # Test Log levels
    app.logger.debug("debug log info")
    app.logger.info("Info log information")
    app.logger.warning("Warning log info")
    app.logger.error("Error log info")
    app.logger.critical("Critical log info")
    return app

app = create_app()

输出仅显示错误，并且目前可见较低的日志

 * Restarting with stat
[2022-12-12 17:38:39,375] ERROR in __init__: Error log info
[2022-12-12 17:38:39,375] CRITICAL in __init__: Critical log info