python - 运行 urllib 审核请求时出现无效 URL 错误

Question

我的代码如下:

import urllib.request as urllib

def read_text():
    quotes = open(r"C:\Users\hjayasinghe2\Desktop\Hasara Work\Learn\demofile.txt")
    contents_of_file = quotes.read()
    print(contents_of_file)
    quotes.close()
    check_pofanity(contents_of_file)

def check_pofanity(text_to_check):
    connection = urllib.urlopen("http://www.wdyl.com/profanity?q= " + text_to_check)
    output = connection.read()
    print(output)
    connection.close()

read_text()

我得到的错误是这样的:

Traceback (most recent call last):
  File "C:/Users/hjayasinghe2/Desktop/Hasara Work/Learn/check_profanity.py", line 16, in <module>
    read_text()
  File "C:/Users/hjayasinghe2/Desktop/Hasara Work/Learn/check_profanity.py", line 8, in read_text
    check_pofanity(contents_of_file)
  File "C:/Users/hjayasinghe2/Desktop/Hasara Work/Learn/check_profanity.py", line 11, in check_pofanity
    connection = urllib.urlopen("http://www.wdyl.com/profanity?q= " + text_to_check)
  File "C:\Users\hjayasinghe2\AppData\Local\Programs\Python\Python37-32\lib\urllib\request.py", line 222, in urlopen
    return opener.open(url, data, timeout)
  File "C:\Users\hjayasinghe2\AppData\Local\Programs\Python\Python37-32\lib\urllib\request.py", line 525, in open
    response = self._open(req, data)
  File "C:\Users\hjayasinghe2\AppData\Local\Programs\Python\Python37-32\lib\urllib\request.py", line 543, in _open
    '_open', req)
  File "C:\Users\hjayasinghe2\AppData\Local\Programs\Python\Python37-32\lib\urllib\request.py", line 503, in _call_chain
    result = func(*args)
  File "C:\Users\hjayasinghe2\AppData\Local\Programs\Python\Python37-32\lib\urllib\request.py", line 1345, in http_open
    return self.do_open(http.client.HTTPConnection, req)
  File "C:\Users\hjayasinghe2\AppData\Local\Programs\Python\Python37-32\lib\urllib\request.py", line 1317, in do_open
    encode_chunked=req.has_header('Transfer-encoding'))
  File "C:\Users\hjayasinghe2\AppData\Local\Programs\Python\Python37-32\lib\http\client.py", line 1244, in request
    self._send_request(method, url, body, headers, encode_chunked)
  File "C:\Users\hjayasinghe2\AppData\Local\Programs\Python\Python37-32\lib\http\client.py", line 1255, in _send_request
    self.putrequest(method, url, **skips)
  File "C:\Users\hjayasinghe2\AppData\Local\Programs\Python\Python37-32\lib\http\client.py", line 1117, in putrequest
    raise InvalidURL(f"URL can't contain control characters. {url!r} "
http.client.InvalidURL: URL can't contain control characters. '/profanity?q= Video provides a powerful way to help you prove your point. When you click Online Video, you can paste in the embed code for the video you want to add.' (found at least ' ')

Answer 1

您需要对查询进行 URL 编码。尝试这样的事情:

import urllib, urllib.parse
url = "http://www.wdyl.com/profanity?q=" + urllib.parse.quote(text_to_check)
connection = urllib.urlopen(url)

参见https://docs.python.org/3/library/urllib.parse.html#urllib.parse.quote