c# - Window_Loaded 事件线程错误中的后台线程

Question

我必须加载一个窗口，在 Window_Loaded 中，我必须加载一些变量并将其显示在 Window 上。

private void Window_Loaded_1(object sender, RoutedEventArgs e)
{         
    BackgroundWorker worker = new BackgroundWorker();

    worker.DoWork += (o, ea) =>
    {
        try
        {
            //code to download some variables which will show on UI of Window Loading
        }
        catch (Exception ex)
        {
            //The calling thread cannot access this object because a different thread owns it.
        }
    };

    worker.RunWorkerCompleted += (o, ea) =>
    {

    };

    worker.RunWorkerAsync();
}

但是我遇到了线程异常。有什么方法可以在 Backgroundworker 的 DoWork 窗口中显示变量值？

Answer 1

您应该在 DoWork 中检索您需要的数据部分，然后将其分配给 ea.Result , 这将使它在 RunWorkerCompleted 中可用部分。

在RunWorkerCompleted部分，您可以访问 ea.Result再次，将对象转换回您在 DoWork 中分配的任何类型，并根据需要将数据应用到您的 UI 控件。

worker.DoWork += (o, ea) =>
{
    ea.Result = GetMyData();
};

worker.RunWorkerCompleted += (o, ea) =>
{
    var myData = (myDataType)ea.Result;

    // Assign myData as needed to UI components...
};