python - 我如何让怪物存在于 def main() 战斗(怪物)中

Question

我有一个它正在选择的怪物列表。

    def monsters():
    whatMonster = random.randint(0, 25)
    monster = pickMonster[whatMonster]
    print(monster.Name)
    print("life =", monster.life)
    print("EXP =", monster.exp)
    return monster

def Battle(monster):

    def attack(monster):
        print(monster.Name)
        print("life =", monster.life)
        print("EXP =", monster.exp)
        print()
        print("level", player.lvl)
        print("HP =", player.life)
        print("Ammor =", player.Def)
        pExp = 0
        pExp = monster.exp + pExp

    action = input(" will you [A]ttack or [R]un   ")
    if action == "A":
        print("you attack")
        attack(monster)
    if action == "R":
        print("You runaway")
    return attack
    return monster

def main():
        loop = True
        header()
        print()
        while loop == True:
            game_loop()
            print()
            monsters()
            print()
            player()
            Battle(monster)
            print()

它向我发送了这种类型的错误:attack() 缺少 1 个必需的位置参数:对我来说是“怪物”，我无法弄清楚这意味着什么

Answer 1

您的 attack() 函数采用单个位置参数 monster (您在定义函数时规定了此要求):

def attack(monster):
    ...

当你这样调用它时:

if action == "A":
    print("you attack")
    attack()

您未能传递该参数，从而导致错误。相反，您需要在调用函数时将 monster 对象传递给该函数:

attack(monster)

从查看其余代码来看，您似乎可以执行以下操作:

random_monster = monsters()
...
attack(random_monster)