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python - 反规范化 tensorflow

转载 作者:太空宇宙 更新时间:2023-11-03 20:11:24 25 4
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我想对神经网络的预测进行非规范化。我首先标准化我的基本事实,并将其标准值和平均值保存在 numpy 数组中:

def norm(x):
return ((x - x.mean()) / x.std())

norm_y_train_n = norm(y_train_n)
mean_y_train_n = y_train_n.mean
std_y_train_n = y_train_n.std

然后我训练我的网络:

history = model.fit(x_train_n, norm_y_train_n, batch_size=10, epochs=200, validation_split=0.1, shuffle=True, callbacks=[es])

我想将数据非规范化为原始分布,以便我可以在有意义的范围内解释均方根误差,如下所示:

def rmse_denorm(y_true, y_pred):
return backend.sqrt(backend.mean(backend.square((y_pred*std_y_train_n + mean_y_train_n) - (y_true*std_y_train_n+mean_y_train_n))))

但我不能,如果我尝试使用 tf.convert_to_tensor 将 numpy 值转换为张量值,如下所示:

def rmse_denorm(y_true, y_pred):
return backend.sqrt(backend.mean(backend.square((y_pred*tf.convert_to_tensor(std_y_train_n) + tf.convert_to_tensor(mean_y_train_n)) - (y_true*tf.convert_to_tensor(std_y_train_n)+tf.convert_to_tensor(mean_y_train_n)))))

我会收到此错误:

Failed to convert object of type <class 'builtin_function_or_method'> to Tensor. Contents: <built-in method std of numpy.ndarray object at 0x7ff00811aee0>. Consider casting elements to a supported type.

如果我想转换张量值:

 def rmse_denorm(y_true, y_pred):
return backend.sqrt(backend.mean(backend.square((tf.dtypes.cast(y_pred)*std_y_train_n + mean_y_train_n) - (tf.dtypes.cast(y_true)*std_y_train_n+mean_y_train_n))))

我收到此错误:

TypeError: cast() missing 1 required positional argument: 'dtype'

我该怎么做?

最佳答案

尝试创建 2 个 tf.constant:

std_const = tf.constant(std_y_train_n)
mean_const = tf.constant(mean_y_train_n)
def rmse_denorm(y_true, y_pred):
return backend.sqrt(backend.mean(backend.square((y_pred*std_const + mean_const) - (y_true*std_const+mean_const))))

关于python - 反规范化 tensorflow ,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/58697729/

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