c# - CMD C# Window应用程序ProcessStartInfo

Question

我需要从 CMD 运行一些东西。在 C# 窗口中。

ProcessStartInfo info = new ProcessStartInfo("cmd.exe");
//info.Arguments = "/K control /name Microsoft.DevicesAndPrinters";
info.Arguments = @"/K cd ../../../../FilesMigration/Solution/FilesMigration/bin/Debug ";
Process.Start(info);

它确实会启动 cmd 并转到指定位置，但现在我需要使用其参数运行“fileMigration.exe”。

我试过这样的:

info.Arguments = "/K filesmigration \"Data Source=(local)/SQLExpress;Initial Catalog=FilesMigration;Integrated Security=true; Connection Timeout=30\""
                          + " \"C:/Programing/api/PE_API_Tester/FilesMigration/SCD File System/For Ella/K_Root\""
                          + " \"C:/Programing/api/PE_API_Tester/FilesMigration/SCD File System/For Ella/U_Root_Analysis_Clusters\""
                          + " \"C:/Programing/api/PE_API_Tester/FilesMigration/SCD File System/For Ella/U_Root_Analysis_Flows\""
                          + " \"C:/Programing/api/PE_API_Tester/FilesMigration/SCD File System/For Ella/U_Root_AtpSoftware_MatrixAtp\""
                          + " \"notepad\""
                          + " \"CO1\""
                          + " \"V1\"";
Process.Start(info);

不过好像是在老地方找。我也试过“Console.write”，但它什么也没做。

知道如何正确书写吗？

Answer 1

尝试设置 WorkingDirectory属性而不是自己传递命令

ProcessStartInfo info = new ProcessStartInfo("cmd.exe");
info.WorkingDirectory = @"../../../../FilesMigration/Solution/FilesMigration/bin/Debug ";
info.Arguments = "/K filesmigration ......";
Process.Start(info);

请检查提供此属性在 UseShellExecute 时的不同行为的链接。是假的