c# - Task.Factory.StartNew 传递返回值

Question

我得到了以下方法，我想传递 dosleep 方法的返回值:

static void Main(string[] args)
{
    var t1 = Task.Factory.StartNew(() => dosleep(2000));
    var t2 = Task.Factory.StartNew(() => dosleep(1000));
    Task.WaitAll(t1,t2);
    Console.WriteLine("All Done in {0} milliseconds!"); //t1+t2 here!!
}

public static int dosleep(int Milliseconds)
{
    System.Threading.Thread.Sleep(Milliseconds);
    Console.WriteLine("Task finished");
    return Milliseconds;
}

Answer 1

使用 Result任务对象的属性

Console.WriteLine("All Done in {0} milliseconds!", t1.Result + t2.Result);