python - 替换列表中的字符

Question

我写了一个小游戏简而言之，用户看到隐藏的单词并需要猜测出现的字母。我成功了大部分，但是当字母多次出现在单词中时，它无法完成单词。

def len_of_word(word):
   return word.replace(word,'_'*len(word))

def show_hidden_word(secret_word, old_letters_guessed):
    hidden = len_of_word(secret_word)
    new_string = list(hidden)
    x = 0
    for i in old_letters_guessed:
       if i in secret_word:
          x = secret_word.find(i)
          new_string[x] = new_string[x].replace(new_string[x], i)
    return " ".join(new_string)
print(show_hidden_word("aviva" , ['m', 'a', 'i', 'r', 'v', 'o', 'm']))

在这种情况下，打印将是

a v i _ _

Answer 1

迭代secret_word而不是old_letters_guessed。为了保持你的结构:

def len_of_word(word):
   return word.replace(word,'_'*len(word))

def show_hidden_word(secret_word, old_letters_guessed):
    hidden = len_of_word(secret_word)
    new_string = list(hidden)
    x = 0
    for i, l in enumerate(secret_word):
       if l in old_letters_guessed:
          new_string[i] = l
    return " ".join(new_string)
print(show_hidden_word("aviva" , ['m', 'a', 'i', 'r', 'o', 'm']))

输出:

a _ i _ a