c# - 并行计算多个值。等待所有线程完成

Question

在 C# 中执行以下操作的惯用且最快的方法是什么？假设我有一个具有三个值的类(它始终是三个值，因此可以预分配 3 个任务):

public class AggregateValues
{
    public double A { get; set;}
    public double B { get; set;}
    public double C { get; set;}
}

public AggregateValues Compute()
{
     //How do I parallize these?
     AggregateValues av = new AggregateValues();
     av.A =  ComputeA();
     av.B =  ComputeB();
     av.C =  ComputeC();

     //Wait for ComputeA, ComputeB, ComputeC to be done

     return av;
}

public double ComputeA()
{
    // Complicated code
}

public double ComputeB()
{
   // Complicated code
}

public double ComputeC()
{
   // Complicated code
}

Answer 1

你可以使用 Task.WaitAll等待所有任务完成的方法。下面提供了针对您的案例的简单解决方案。

public AggregateValues Compute()
{
    //How do I parallize these?
    AggregateValues av = new AggregateValues();

    Task taskA = Task.Factory.StartNew(() => av.A = ComputeA());
    Task taskB = Task.Factory.StartNew(() => av.B = ComputeB());
    Task taskC = Task.Factory.StartNew(() => av.C = ComputeC());

    //Wait for ComputeA, ComputeB, ComputeC to be done
    Task.WaitAll(taskA, taskB, taskC);

    return av;
}

等待Task.WhenAll也可用于等待所有任务完成。