c# - Controller 返回神秘 View

Question

我在 SampleController 中有以下 Details 操作:

public ActionResult Details(int sampleNumber)
{
    var sample = (Sample)Session["sample"];
    if (sample == null)
    {
        var pallet = (Pallet)Session["pallet"];

        sample = pallet.Samples.First(s
            => s.SampleNo.Equals(sampleNumber));

        if (sample.Defects.Count < 1) // Postback issue?
        {
            var access = new Access();

            sample.Defects = access.GetDefects(pallet.Grv.GRVNo,
                pallet.PalletSeq, sampleNumber);
            sample.GetImagePaths();
            sample.Pallet = pallet;

            Session["sample"] = sample;
        }
    }

    return View(sample);
}

这个更新 Action :

public ActionResult Update(IEnumerable<HttpPostedFileBase> files, Sample sample)
{
    var pallet = (Pallet)Session["pallet"];

    sample.Pallet = pallet;
    sample.SaveImages(files);

    access.UpdateSample(sample);
    access.UpdateDefects(sample);

    Session["sample"] = sample;

    return View("Details", sample);
}

我正在尝试调试问题，但不知何故 return View("Details", sample); 行没有调用上面的 Details 操作(断点确实不要停止代码)。

它确实返回了所选示例 的 View ，但是Details 中的所有操作都没有发生。

我尝试将 return 语句更改为

return View("Details", sample.SampleNo);

要匹配 Details 的签名，但我得到:

The model item passed into the dictionary is of type 'System.Int32', but this dictionary requires a model item of type 'MVCQCPage.Models.Sample'.

这怎么可能？ Details 操作不要求 Sample 参数，那么为什么这不只是返回 Details 并传入 sampleNo (int) 值？

请注意，上面的 Details 操作是 SampleController 中该名称的唯一方法。

Answer 1

您需要执行RedirectToAction

public ActionResult Update(IEnumerable<HttpPostedFileBase> files, Sample sample)
{
 var pallet = (Pallet)Session["pallet"];

  sample.Pallet = pallet;
  sample.SaveImages(files);

  access.UpdateSample(sample);
  access.UpdateDefects(sample);

  Session["sample"] = sample;

  return RedirectToAction("Details", sample.SampleNo);
}

请查看https://msdn.microsoft.com/en-us/library/system.web.mvc.controller.redirecttoaction(v=vs.118).aspx