matlab - 在 Python 中使用 matplotlib 绘制多个数据点

Question

我最近从 MATLAB 切换到 Python 进行数据分析，我正在使用 matplotlib 进行数据可视化。如果我想可视化的数据点数量很少，这很好用。但是，如果我想想象一下，例如

import matplotlib.pyplot as plt
signal = [round(random.random() * 100) for i in xrange(0, 1000000)]
plt.plot(signal)
plt.show()

我收到一个错误:

Exception in Tkinter callback
Traceback (most recent call last):
  File "/usr/lib/python2.7/lib-tk/Tkinter.py", line 1489, in __call__
    return self.func(*args)
  File "/usr/lib/pymodules/python2.7/matplotlib/backends/backend_tkagg.py", line 276, in resize
    self.show()
  File "/usr/lib/pymodules/python2.7/matplotlib/backends/backend_tkagg.py", line 348, in draw
    FigureCanvasAgg.draw(self)
  File "/usr/lib/pymodules/python2.7/matplotlib/backends/backend_agg.py", line 451, in draw
    self.figure.draw(self.renderer)
  File "/usr/lib/pymodules/python2.7/matplotlib/artist.py", line 55, in draw_wrapper
    draw(artist, renderer, *args, **kwargs)
  File "/usr/lib/pymodules/python2.7/matplotlib/figure.py", line 1034, in draw
    func(*args)
  File "/usr/lib/pymodules/python2.7/matplotlib/artist.py", line 55, in draw_wrapper
    draw(artist, renderer, *args, **kwargs)
  File "/usr/lib/pymodules/python2.7/matplotlib/axes.py", line 2086, in draw
    a.draw(renderer)
  File "/usr/lib/pymodules/python2.7/matplotlib/artist.py", line 55, in draw_wrapper
    draw(artist, renderer, *args, **kwargs)
  File "/usr/lib/pymodules/python2.7/matplotlib/lines.py", line 562, in draw
    drawFunc(renderer, gc, tpath, affine.frozen())
  File "/usr/lib/pymodules/python2.7/matplotlib/lines.py", line 938, in _draw_lines
    self._lineFunc(renderer, gc, path, trans)
  File "/usr/lib/pymodules/python2.7/matplotlib/lines.py", line 978, in _draw_solid
    renderer.draw_path(gc, path, trans)
  File "/usr/lib/pymodules/python2.7/matplotlib/backends/backend_agg.py", line 145, in draw_path
    self._renderer.draw_path(gc, path, transform, rgbFace)
OverflowError: Allocated too many blocks

你能告诉我在这种情况下你会怎么做吗？你在降低数据采样率吗？如果我在 MATLAB 中执行相同的绘图，即使有更多的数据点，我以前也没有遇到过这个问题。

Answer 1

不确定您要显示的确切内容，但您可以将情节更改为 '.'，它会起作用。

import random
import pylab as plt
signal = [round(random.random() * 100) for i in xrange(0, 1000000)]
plt.plot(signal, '.')
plt.show()

您可以通过使用 matlotlibrc 文件进行自定义来获得所需的内容，文档为 here