使用 or 运算符时，Python 正则表达式的模糊搜索不会返回所有匹配项

Question

例如，当我使用时

regex.findall(r"(?e)(mazda2 standard){e<=1}", "mazda 2 standard")

，答案照常是['mazda 2 standard']。

但是当我使用时

regex.findall(r"(?e)(mazda2 standard|mazda 2){e<=1}", "mazda 2 standard")

或

regex.findall(r"(?e)(mazda2 standard|mazda 2){e<=1}", "mazda 2 standard", overlapped=True)

，输出根本不包含“mazda 2 standard”。如何使输出也包含“mazda 2 standard”？

Answer 1

参见PyPi regex documentation :

By default, fuzzy matching searches for the first match that meets the given constraints. The ENHANCEMATCH flag will cause it to attempt to improve the fit (i.e. reduce the number of errors) of the match that it has found.

The BESTMATCH flag will make it search for the best match instead.

您通过代码获得 mazda 2，因为此匹配不包含错误。

因此，请使用 BESTMATCH 标志(内联修饰符选项是 (?b)):

>>> import regex
>>> regex.findall(r"(?be)(mazda2 standard|mazda 2){e<=1}", "mazda 2 standard")
['mazda 2 standard']
>>>