c# - 如何重命名返回的元组项目？

Question

我是 C# 新功能 Called as Tuples 的新手。我在元组上写了一些代码。当方法返回元组时(元组包含多个值)。

我-我

string firstNumber = separateNumbers.Item1;
string secondNumber = separateNumbers.Item2;
string thirdNumber = separateNumbers.Item3;
string fourthNumber = separateNumbers.Item4;

在真实场景中，识别哪个项目包含哪个值变得很复杂？

所以我想提供一些特定的名称，而不是 item1、item2 等...怎么做 ？

提前致谢。

代码:

namespace CSharp_Tuples
{
    class Program
    {
        static void Main(string[] args)
        {
            string PhoneNumbers = "+92315 +92316 +92317 +92318";
            var separateNumbers = GetIndividualNumbers(PhoneNumbers);

            string firstNumber = separateNumbers.Item1;
            string secondNumber = separateNumbers.Item2;
            string thirdNumber = separateNumbers.Item3;
            string fourthNumber = separateNumbers.Item4;

            Console.WriteLine(firstNumber);
            Console.WriteLine(secondNumber);
            Console.WriteLine(thirdNumber);
            Console.WriteLine(fourthNumber);

        }
        static Tuple<string, string, string, string> GetIndividualNumbers(string allNumbers)
        {
            string[] numbers  = allNumbers.Split(' ');
            return Tuple.Create<string,string,string,string>(numbers[0],numbers[1],numbers[2],numbers[3]);
        }
    }
}

Answer 1

C# 7.0 tuples feature使用 ValueTuple ，不是旧的Tuple .

使用该功能，您可以执行以下操作:

namespace CSharp_Tuples
{
    class Program
    {
        static void Main(string[] args)
        {
            string PhoneNumbers = "+92315 +92316 +92317 +92318";

            var numbers = UsingValueTuple(PhoneNumbers);

            Console.WriteLine("firstNumber : " + numbers.firstNumber);
            Console.WriteLine("secondNumber : " + numbers.secondNumer);
            Console.WriteLine("thirdNumber : " + numbers.thirdNumber);
            Console.WriteLine("fourthNumber : " + numbers.fourthNumber);
        }

        static (string firstNumber, string secondNumer, string thirdNumber, string fourthNumber) UsingValueTuple(string allNumbers)
        {
            string[] numbers = allNumbers.Split(' ');
            return (numbers[0], numbers[1], numbers[2], numbers[3]);
        }
    }
}