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Matlab:如何在图像中弯曲线条

转载 作者:太空宇宙 更新时间:2023-11-03 19:37:34 27 4
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我手头有一张图片(png 格式)。限制椭圆(代表原子核)的线太直了,这是不切实际的。如何从图像中提取线条并使它们弯曲,前提是它们仍然包围着原子核。

图片如下:
enter image description here

弯曲后

enter image description here

编辑:如何将answer2 中的Dilation And Filter 部分翻译成Matlab 语言?我想不通。

最佳答案

好的,这是一种涉及获得“自然”非对称外观所需的多个随机化步骤的方法。

我在 Mathematica 中发布实际代码,以防万一有人关心将它翻译成 Matlab。

(* A preparatory step: get your image and clean it*)
i = Import@"http://i.stack.imgur.com/YENhB.png";
i1 = Image@Replace[ImageData[i], {0., 0., 0.} -> {1, 1, 1}, {2}];
i2 = ImageSubtract[i1, i];
i3 = Inpaint[i, i2]

enter image description here

(*Now reduce to a skeleton to get a somewhat random starting point.  
The actual algorithm for this dilation does not matter, as far as we
get a random area slightly larger than the original elipses *)
id = Dilation[SkeletonTransform[
Dilation[SkeletonTransform@ColorNegate@Binarize@i3, 3]], 1]

enter image description here

(*Now the real random dilation loop*)
(*Init vars*)
p = Array[1 &, 70]; j = 1;
(*Store in w an image with a different color for each cluster, so we
can find edges between them*)
w = (w1 =
WatershedComponents[
GradientFilter[Binarize[id, .1], 1]]) /. {4 -> 0} // Colorize;
(*and loop ...*)
For[i = 1, i < 70, i++,
(*Select edges in w and dilate them with a random 3x3 kernel*)
ed = Dilation[EdgeDetect[w, 1], RandomInteger[{0, 1}, {3, 3}]];
(*The following is the core*)
p[[j++]] = w =
ImageFilter[ (* We apply a filter to the edges*)
(Switch[
Length[#1], (*Count the colors in a 3x3 neighborhood of each pixel*)
0, {{{0, 0, 0}, 0}}, (*If no colors, return bkg*)
1, #1, (*If one color, return it*)
_, {{{0, 0, 0}, 0}}])[[1, 1]] (*If more than one color, return bkg*)&@
Cases[Tally[Flatten[#1, 1]],
Except[{{0.`, 0.`, 0.`}, _}]] & (*But Don't count bkg pixels*),
w, 1,
Masking -> ed, (*apply only to edges*)
Interleaving -> True (*apply to all color chanels at once*)]
]

结果是:

enter image description here

编辑

对于面向 Mathematica 的读者来说,最后一个循环的功能代码可能更容易(也更短):

NestList[
ImageFilter[
If[Length[#1] == 1, #1[[1, 1]], {0, 0, 0}] &@
Cases[Tally[Flatten[#1, 1]], Except[{0.` {1, 1, 1}, _}]] & , #, 1,
Masking -> Dilation[EdgeDetect[#, 1], RandomInteger[{0, 1}, {3, 3}]],
Interleaving -> True ] &,
WatershedComponents@GradientFilter[Binarize[id,.1],1]/.{4-> 0}//Colorize,
5]

关于Matlab:如何在图像中弯曲线条,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/7963459/

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