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python - 如何为 Django Pastebin 应用程序中的所有粘贴创建链接列表?

转载 作者:太空宇宙 更新时间:2023-11-03 19:29:46 24 4
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我已经使用 Django 设置了一个 Pastebin 应用程序,但我希望能够创建指向主页模板上每个单独粘贴的链接列表。我一直在尝试许多不同的事情,但正在努力找出答案。

这是我迄今为止在模板上的内容,该应用程序名为 oxybeles:

<ul>
{% for ????? in ????? %}
<a href="{% url oxybeles_detail item.uuid %}">A Link</a>
{% endfor %}
</ul>

这是相关的后端代码:

模型.py

class PastedItem(models.Model):

uuid = models.CharField(_('identifier'), max_length=36, unique=True)
artist = models.CharField(_('artist'), max_length=50)
album = models.CharField(_('album'), max_length=50)
in_response_to = models.ForeignKey('self', related_name='responses',
blank=True, null=True, verbose_name=_('in response to'))
user = models.ForeignKey(User, related_name="pasted_items",
verbose_name=_('user'))
pasted_at = models.DateTimeField(_('pasted at'), auto_now_add=True)

def __unicode__(self):
return self.uuid

def save(self):
if not self.uuid:
self.uuid = str(uuid4()) # random so it can't be easily guessed
super(PastedItem, self).save()

def get_absolute_url(self):
return ('oxybeles_detail', (), { 'slug': self.uuid })
get_absolute_url = models.permalink(get_absolute_url)

View .py

def new(request, form_class=PastedItemForm, template_name="oxybeles/new.html"):

form = form_class()
if request.method == 'POST':
if request.POST["action"] == "paste":
form = form_class(request.user, request.POST, request.FILES)
if form.is_valid():
item = form.save(commit=False)
item.user = request.user
item.save()
request.user.message_set.create(
message=ugettext("Your album has been saved."))
# some problem with ugettext_lazy here
return HttpResponseRedirect(reverse('oxybeles_detail',
args=(item.uuid,)))
return render_to_response(template_name,
{'form': form,},
context_instance=RequestContext(request))
new = login_required(new)

最佳答案

for item in items

其中 items 是一个充满 PastedItem 的查询集:

items = PastedItem.objects.all()

并且项目被提供给模板:

{'form':form, 'items': items}

关于python - 如何为 Django Pastebin 应用程序中的所有粘贴创建链接列表?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/6500262/

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