c# - 许多添加/更改方法和构造函数重载是 DDD 的结果吗？

Question

我有一个类:

    public class Person
{
    public string FirstName { get; private set; }
    public string LastName { get; private set; }
    public string Email { get; private set; }
    public string Telephone { get; private set; }
    public Address Address { get; private set; }

    public Person(string firstName, string lastName)
    {
        //do null-checks
        FirstName = firstName;
        LastName = lastName;
        Address = new Address();
    }

    public void AddOrChangeEmail(string email)
    {
        //Check if e-mail is a valid e-mail here
        Email = email;
    }

    public void AddOrChangeTelephone(string telephone)
    {
        //Check if thelephone has correct format and valid symbols
        Telephone = telephone;
    }

    public void AddOrChangeAdress(Address address)
    {
        Address = address;
    }

构造函数中没有的属性是可选的，即此人不需要电子邮件、地址或电话。但是，我想给类的用户一个创建对象的机会，而不必先提供所需的信息，然后再找出使用什么方法来添加信息。

问题:

1. 创建 3 个额外的重载来为他们提供该选项是否正确？
2. 我应该允许可选属性的公共(public) setter 并在那里进行验证吗？
3. 如果这个人结婚并更改了姓氏，我是否需要其他方法来更改姓氏，或者我是否也应该将此 setter 公开，并且只在构造函数中要求它们？

Answer 1

1. 没有。
2. 是
3. 公开。

假设您将在 AddOrChange 方法中包含更多代码，例如格式化逻辑或验证，那么我将执行以下操作。否则，我将完全摆脱 AddOrChange 方法:

public class Person
{
    private string _email = string.empty;
    private string _telephone = string.empty;
    private Address _address = new Address();

    public string FirstName { get; set; }
    public string LastName { get; set; }
    public string Email { 
        get { return _email }
        set { AddOrChangeEmail(value); }
    }
    public string Telephone { 
        get { return _telephone;}
        set { AddOrChangeTelephone(value); }
     }
    public Address Address { 
        get { return _address;  }
        set { AddOrChangeAddress(value); }
    }

    public Person(string firstName, string lastName)
    {
        //do null-checks
        FirstName = firstName;
        LastName = lastName;
    }

    private void AddOrChangeEmail(string email)
    {
        //Check if e-mail is a valid e-mail here
        _email = email;
    }

    private void AddOrChangeTelephone(string telephone)
    {
        //Check if thelephone has correct format and valid symbols
        _telephone = telephone;
    }

    private void AddOrChangeAddress(Address address)
    {
        _address = address;
    }
}

---

要使用此类，您可以执行以下任一操作:

Person p = new Person("Tom", "Jones");
p.Telephone = "9995551111";

或

Person p = new Person("Tom", "Jones") { Telephone = "9995551111", Email="spamme@ms.com" }